how jump from staying for output of shell execute after run in an php script?

Question

I have this sample code called main.php:

<?php
shell_exec('C:\wamp\bin\php\php5.4.3\php.exe a.php');
shell_exec('C:\wamp\bin\php\php5.4.3\php.exe b.php');
?>

when execute this script after executing first shell_exec it staying until finishing first shell_exec and then run second.

but I want that script dont stay for finishing first shell_exec and its output and runs second.

now how can I do this?

I have several scripts and I need to run them Simultaneously by a main script and control them by it. but I dont know that how to run my scripts Simultaneously from inside of this main script?

update1: I cant run a.php and b.php by cron jobs because their finishing time is unknown. maybe a.php finished after 1 hour or 10 minutes and b.php as same as a.php too.

update2: I founded a solution in this page:

Is there a way to use shell_exec without waiting for the command to complete?

what is the use-case? Possible solutions would include ajax or for example scheduled jobs if it's just something that needs to run periodically. — jeroen
– jeroen, Commented Jul 23, 2013 at 1:14
I dont run these scripts by browser. these scripts must run in background — saeid ezzati
– saeid ezzati, Commented Jul 23, 2013 at 1:25
If you are looking for a shell script, check this question: stackoverflow.com/questions/672719/… — jeroen
– jeroen, Commented Jul 23, 2013 at 1:28
@jeroen I dont understand them. I only want a simple way to run an cmd command from inside of a php script and dont stay for its output and execute rest of my script codes :( — saeid ezzati
– saeid ezzati, Commented Jul 23, 2013 at 1:40

pradosh nair · Accepted Answer · 2013-08-04 12:41:48Z

1

If i understand you wish to run a background process on a Windows box.Suggest try this...

<?php
    shell_exec('start /b C:\wamp\bin\php\php5.4.3\php.exe a.php');
    shell_exec('start /b C:\wamp\bin\php\php5.4.3\php.exe b.php');
?>

answered Aug 4, 2013 at 12:41

pradosh nair

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