how to display particular array combination?

Question

i want to display following array in output as 246,357 that is donot process first subarray and also the remaining subarray combination should be like $array[1][0].$array[2][0].$array[3][0],similarly combination should be $array[1][1].$array[2][1].$array[3][1]

$array=[
          [0,1],
          [2,3],
          [4,5],
          [6,7]
       ];

i have written follwing code but could not bypass first subarray so my output is 0246,1357.plz help.

foreach($array as $n)
{
    $a.=$n[0];
    $b.=$n[1];
}
echo "$a".","."$b";

PleaseStand · Accepted Answer · 2013-07-24 09:00:57Z

2

One way to skip the first element would be to use a flag variable $first:

$first = true;
foreach ($array as $n) {
    if ($first) {
        $first = false;
    } else {
        $a .= $n[0];
        $b .= $n[1];
    }
}

Another way would be to remove the first element from the array, so it will be skipped over:

unset($array[0]);

Or check the key from within the foreach loop:

foreach ($array as $k => $n) {
    if ($k > 0) {
        $a .= $n[0];
        $b .= $n[1];
    }
}

Yet another way would be to use array_shift(), which changes numeric keys in addition to removing the first element:

array_shift($array);

Finally, because your array contains only consecutive integer keys starting from 0, you could just use a normal for loop:

for ($i = 1; $i < count($array); $i++) {
    $a .= $array[$i][0];
    $b .= $array[$i][1];
}

edited Jul 24, 2013 at 9:00

answered Jul 24, 2013 at 8:25

PleaseStand

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Comments

Sundar · Accepted Answer · 2013-07-24 08:25:42Z

1

This will help you to skip the first array

foreach($array as $key => $n)
{
 if($key>0)
 {
    $a.=$n[0];
    $b.=$n[1];
 }
}

answered Jul 24, 2013 at 8:25

Sundar

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Comments

Vivek Sadh · Accepted Answer · 2013-07-24 08:27:45Z

1

You can use this:-

$flag = true;
foreach ($array as $n) {
    if ($flag==false) {
        $a .= $n[0];
        $b .= $n[1];
    } else {
        $flag = false;
    }
}

answered Jul 24, 2013 at 8:27

Vivek Sadh

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Comments

Hein Andre Grønnestad · Accepted Answer · 2013-07-24 08:30:18Z

1

Skip the first sub array by using a regular for loop which starts at offset 1 instead of the foreach loop.

for ($i = 1; $i <= count($array); $i++) {
    $a.=$array[$i][0];
    $b.=$array[$i][1];
}

Alternatives

You could also remove the first sub array with array_shift() and use the code you already have.
Use a flag as many of the other answers suggests (I think it's over complicated though).

Another code improvement suggestion

The line

echo "$a".","."$b";`

Can be written as

echo "{$a},{$b}";

Which I think is a lot more readable.

edited Jul 24, 2013 at 8:30

answered Jul 24, 2013 at 8:24

Hein Andre Grønnestad

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Comments

Prasanth Bendra · Accepted Answer · 2013-07-24 11:39:31Z

1

Check this anser without any loops :

$array=array(array(0,1),
            array(2,3),
            array(4,5),
            array(6,7)
       );

array_shift($array);
array_unshift($array, null);
$result = array_map("implode",call_user_func_array('array_map', $array));

echo "<pre>";
print_r($result);

Output :

Array
(
    [0] => 246
    [1] => 357
)

answered Jul 24, 2013 at 11:39

Prasanth Bendra

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