json object post to php script in android app

Question

I tried this android code for send json objects to my website

HttpPost httppost = new HttpPost(url);

JSONObject j = new JSONObject();
    j.put("name","name ");

        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        String format = s.format(new Date()); 
    nameValuePairs.add(new BasicNameValuePair("msg",j.toString() ));

       httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                               httpclient.execute(httppost);

And this php code

<?php

$msg=$_POST["msg"]; 

$filename="androidmessages.html";

file_put_contents($filename,$msg."<br />",FILE_APPEND);

$androidmessages=file_get_contents($filename);

echo $androidmessages;
?>

It will show me {"name":"name "} but if i use

httppost.setHeader( "Content-Type", "application/json" );

it will show nothing.I have no before experince about json object post but i think something went wrong.I want to send some user information to my website and display it in web page can you please tell me what i need to change to overcome this problem Thank you

SAGA · Accepted Answer · 2013-07-29 04:41:44Z

2

Finally i got the answer

$msg=json_decode(file_get_contents('php://input'), true); 

$filename="androidmessages_json.html";

file_put_contents($filename,$msg['name']."<br />",FILE_APPEND); 

$androidmessages=file_get_contents($filename);

echo $androidmessages;

answered Jul 29, 2013 at 4:41

SAGA

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Comments

Christian · Accepted Answer · 2013-07-27 22:46:51Z

1

It depends how you want to pass the data to your PHP-script.

If you want to get the JSON as a string in one variable (and maybe others in addition), then you should not use the content-type "application/json". If you want to only post the JSON without any variable, you can do the following instead:

HttpPost httppost = new HttpPost(url);
JSONObject j = new JSONObject();
j.put("name","name ");
httppost.setEntity(new StringEntity(j.toString());
httpclient.execute(httppost);

As you can imagine from the code you do not have the JSON in one POST-var only but in total.

answered Jul 27, 2013 at 22:46

Christian

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6 Comments

SAGA Over a year ago

Thank you christian. and i want to know what are different between these 2 methods (String in one variable and Post json without variable)

Christian Over a year ago

Post without variable means you will not get it in your $_POST-array, but have to get it by json_decode(file_get_contents('php://input'), true);

SAGA Over a year ago

$msg=json_decode(file_get_contents('php://input'), true); $filename="androidmessages.html"; file_put_contents($filename,$msg."<br />",FILE_APPEND); $androidmessages=file_get_contents($filename); echo $androidmessages; Is this correct?

Christian Over a year ago

why do you need the file? I would just say echo json_decode(file_get_contents('php://input'), true);

SAGA Over a year ago

It will doesn't show anything but if i use file it will show "Array" but it also doesn't show my details in json object

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