Parsing xml file error

Question

I'm trying to transform an XML file into a document like this:

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document document = db.parse("C:/xml/41111208890622000144550010000000011000003066-nfe.xml"); 
Document document = db.parse(new InputSource(new StringReader("C:/xml/41111208890622000144550010000000011000003066-nfe.xml")));

but it is giving the error message:

Exception in thread "main" org.xml.sax.SAXParseException; lineNumber: 1; columnNumber: 1;

someone knows what to do?

What's the content of the file?

Qwerky
– Qwerky

2013-07-30 15:11:45 +00:00
Commented Jul 30, 2013 at 15:11 — Qwerky
– Qwerky, Commented Jul 30, 2013 at 15:11

Jon Skeet · Accepted Answer · 2013-07-30 21:25:09Z

4

You're currently creating a reader containing the string

"C:/xml/41111208890622000144550010000000011000003066-nfe.xml"

and asking the DocumentBuilder to parse that as if it were XML, when it's clearly not. (I'm referring to the second parse call, which I suspect is the one in your actual code. The code you've provided wouldn't compile as you've declared document twice.)

You can create a FileInputStream or perhaps an InputStreamReader wrapped around it:

String filename = "C:/xml/41111208890622000144550010000000011000003066-nfe.xml";
try (FileInputStream input = new FileInputStream(filename))
{
    Document document = db.parse(new InputSource(input));
}

(I prefer to use a stream directly, and let the parser detect the encoding.)

Now this call:

Document document = db.parse("C:/xml/...");

would nearly work and may actually work, using DocumentBuilder.parse(String) - it depends on whether parse is happy to handle a filename as a URI. (I've seen some XML APIs that are fine with that, and some that aren't.) If it doesn't work, try using the file:// scheme:

Document document = db.parse("file://C:/xml/...");

edited Jul 30, 2013 at 21:25

answered Jul 30, 2013 at 15:12

Jon Skeet

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6 Comments

forty-two Over a year ago

Not quite. The DocumentBuilder#parse(String) method takes a URL (in string form) and parses the content of that location. This is in fact a safer method than the InputStream version, since the parser is given the base URI (system ID) and can use it for resolving other resources, if needed.

Jon Skeet Over a year ago

@forty-two: When you say "not quite" - unless there are other (relative) resources in the XML, this works fine, right? (My claim of "needing" to do this is wrong, admittedly - will edit that.)

forty-two Over a year ago

"Not quite" referred to the implication that #parse(String) takes an XML string, which it doesn't.

Jon Skeet Over a year ago

@forty-two: I was referring to the second call to parse, which takes an InputSource built with a StringReader. That is trying to parse the filename as if it's XML, which explains the exception. I've clarified slightly - it really doesn't help that the code wouldn't even have compiled.

Jon Skeet Over a year ago

@forty-two: Does my answer make more sense now? I've added a bit about the parse(String) method as well though.

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