php pass array to function as separate variables

Question

i need to know how to pass an array to a function as separate variables, for instance,

function myfunction($var, $othervar) {
}

$myarray = array('key'=>'val', 'data'=>'pair');

here is where I am running into problems, the following doesn't seem to work:

$return = myfunction(extract($myarray));

it should, if I understand correctly, basically be the same as

$return = myfunction($key, $data);

where $key='val' and $data='pair'

can anyone please explain this to me.

possible duplicate of PHP: Array to variable function parameter values — mario
– mario, Commented Jul 31, 2013 at 3:49
what about this: it was: $this->_obj[$key]->$function(extract($vars)); now it's: return call_user_func_array(array(get_class($this->_obj[$key]), $function), $vars); but this doesn't work because a non-static method 'can't' be called statically — Nate
– Nate, Commented Jul 31, 2013 at 3:58
given what you see above, how would you implement array_walk here? — Nate
– Nate, Commented Jul 31, 2013 at 4:02

Shashi · Accepted Answer · 2013-07-31 03:58:26Z

0

If I am understanding your question right then try this

$return = myfunction($myarray["key"],$myarray["data"]);

here we are simply passing the associative array as arguments.

answered Jul 31, 2013 at 3:58

Shashi

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2 Comments

Nate Over a year ago

that's useful but the problem there is that I don't know how many variables there are or what the keys are, i'll post the complete code in an answer below

Nate Over a year ago

should i just ignore the 'Strict Standards' error message and use call_user_func_array?

Nate · Accepted Answer · 2013-07-31 04:06:28Z

0

    public function get($key=null, $function='', array $vars=array()) {
        if ($key==null || !array_key_exists($key, $this->_obj)) {
            return null;
        }

var_dump($vars);

        if (!empty($function)) {
            return $this->_obj[$key]->$function(array_walk($vars));
//          return call_user_func_array(array(get_class($this->_obj[$key]), $function), $vars);
//          return $this->_obj[$key]->$function(extract($vars));
        }
        return $this->_obj[$key];
    }

answered Jul 31, 2013 at 4:06

Nate

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2 Comments

Nate Over a year ago

now with call_user_func_array I'm getting this: Using $this when not in object context in C:\aDomain\profordable\lib\Class_Database.php on line 42 because apparently using call_user_function_array(array('class', 'function'), $vars) with an array as the function name, calls the method statically

Nate Over a year ago

I was passing the class in call_user_func_array as a string instead of as an object, what i have now is below, and it seems to work, although more input would be appreciated

Nate · Accepted Answer · 2013-07-31 04:30:25Z

    public function get($key=null, $function='', array $vars=array()) {
        if ($key==null || !array_key_exists($key, $this->_obj)) {
            return null;
        }
        if (!empty($function)) {
            return call_user_func_array(array($this->_obj[$key], $function), $vars);
        }
        return $this->_obj[$key];
    }

$registry = Registry_Object::Singleton();
//...later on
$registry = $GLOBALS['registry'];
$registry->set('Content', new Content($_SERVER['REQUEST_URI']));
$id = $registry->get('Content', 'GetIdFunc');
$registry->set('DB', 'Database');
$query = $registry->get('DB', 'Read', array("SELECT TITLE, CONTENT FROM APP_CONTENT WHERE ID=$id"));
print '<h1>'.$query[0]['TITLE'].'</h1>';
print Template_Helper::TPL_Paragraphs($query[0]['CONTENT']);

thanks all

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