I have the following code
f = open('BigTestFile','w');
str = '0123456789'
for i in range(100000000):
if i % 1000000 == 0:
print(str(i / 1000000) + ' % done')
f.write(str)
f.close()
When I run it, I get this TypeError:
Traceback (most recent call last):
File "gen_big_file.py", line 8, in <module>
print(str(i / 1000000) + ' % done')
TypeError: 'str' object is not callable
Why is that? How to fix?
Call the variable something other than str.
It is shadowing the str built in function.
It's because you overrode the function str on line 3.
str() is a builtin function in Python which takes care of returning a nice string representation of an object.
Change line 3 from
str = '0123456789'
to
number_string = '0123456789'
str='abc'; print(str). The problem here is that he calls it by saying str() which is not correct, he must use []
1%done. Changing the string name from str to number_string will output what OP is asking for even though that in it self will be incorrect and he'll face the problem you're solving to access a strings char by brackets.You overwrote str which is normally a constructor for strings.
You could just change this line to "{} % done".format(i) if you really don't want to change it.
And if you insist on overwriting the str class instantiator with an actual string then replacing str(i) with "".__class__(i) would fix the error.
First of all, if you want to access the ith element of something, you need to use [i] and not (i). And second, as the others already mentioned, don't override str, the function to obtain any object's string representation.
strits python internal variable