How to remove an array containing certain strings from another array in Python

Question

Example:

a = ['abc123','abc','543234','blah','tete','head','loo2']

So I want to filter out from the above array of strings the following array b = ['ab','2']

I want to remove strings containing 'ab' from that list along with other strings in the array so that I get the following:

a = ['blah', 'tete', 'head']

TerryA · Accepted Answer · 2013-07-31 13:42:05Z

5

You can use a list comprehension:

[i for i in a if not any(x in i for x in b)]

This returns:

['blah', 'tete', 'head']

answered Jul 31, 2013 at 13:42

TerryA

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6 Comments

L P Over a year ago

It gives the original 'a' values

TerryA Over a year ago

@LP What do you mean?

Henrik Andersson Over a year ago

@Haidro your first iteration was wrong. +1 But the readability of this one is horrible :)

TerryA Over a year ago

@limelights I'm on my phone :p

TerryA Over a year ago

@LP Yea, sorry about that. I must have just fixed that after you commented. Anyways, glad I helped :)

|

dawg · Accepted Answer · 2013-07-31 13:49:31Z

2

>>> a = ['abc123','abc','543234','blah','tete','head','loo2']
>>> b = ['ab','2']
>>> [e for e in a if not [s for s in b if s in e]]
['blah', 'tete', 'head']

answered Jul 31, 2013 at 13:49

dawg

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Comments

isaach1000 · Accepted Answer · 2013-07-31 14:02:31Z

1

newA = []
for c in a:
    for d in b:
        if d not in c:
            newA.append(c)
            break
a = newA

edited Jul 31, 2013 at 14:02

answered Jul 31, 2013 at 13:44

isaach1000

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2 Comments

TerryA Over a year ago

Although this is correct, it is a much slower solution (albeit more readable:)). Just a tip, you can use break after the if ... as you don't need to search anymore (this is what any does, btw).

isaach1000 Over a year ago

Actually you are right and it is necessary to avoid adding twice.

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