How can I convert a string with integers to array with integers in java?

Question

I want to convert a string with integers to array with integers in Java. How i can do this?I have an array with strings.Every string is integers. I want to access every string with a click from a button.

 String[] INT_ARRAY={

        //0
        "250,125,20,20,20,40,20,20,20,40,20,20,20,2500",

        //1 
        "233,63,28,63,29,63,28,16,28,17,26,63,29,17,26,16....
                     ........

                 }

   public void onClick(View v) {

        counter++;
        String IntString = INT_ARRAY[counter];

                    String[] parts = IntString.split(",");


          final int[] A = new int[parts.length()];

          for(int i=0; i<parts.length(); i++){

            A[i] = Integer.parseInt(parts(i));

                            Toast.makeText(getApplicationContext(),String.valueOf(A[i]), Toast.LENGTH_SHORT).show();

        }

  }

Pretty must the way you have it, but you have to split the string on , — Leon
– Leon, Commented Jul 31, 2013 at 15:37

Eng.Fouad · Accepted Answer · 2013-07-31 15:43:23Z

3

You need String#spilt() to split the string, something like:

String[] parts = "aa,bb,cc,dd".split(",");

parts now consists of {"aa", "bb", "cc", "dd"}.

Then use the enhanced-for loop to iterate over each part, something like:

for(String part : parts) Log.d("", part);

answered Jul 31, 2013 at 15:43

Eng.Fouad

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Comments

Samuel · Accepted Answer · 2013-07-31 15:43:52Z

So you have a partially-serialized representation of what appears to be an array of integer arrays. From your code, you obviously understand that you need to use parseInt() to convert a string representation of an integer to an int primitive. This part looks good, but you need logic to loop through each comma-separated value in each string. You can use the split() method to create an array of strings from your comma separated list. The entire solution would look like the following:

public void onClick(View v) {

    counter++;
    String IntString = INT_ARRAY[counter];

    final String[] vals = IntString.split(","); // Here we split the comma-separated string
    final int[] A = new int[vals.length];

    for(int i=0; i<vals.length; i++){
        A[i] = Integer.parseInt(vals[i]);
        Toast.makeText(getApplicationContext(),String.valueOf(A[i]), Toast.LENGTH_SHORT).show();
    }

}

Nikola Despotoski · Accepted Answer · 2013-07-31 15:44:25Z

2

private Integer[] splitIntegers(String s){
        Object[] numbersAsString = s.split(",");
        return Arrays.copyOf(numbersAsString, numbersAsString.length, Integer[].class);
}

Calling:

for(String s: INT_ARRAY){
  Integer[] ints = splitIntegers(s);
}

answered Jul 31, 2013 at 15:44

Nikola Despotoski

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4 Comments

Steve P. Over a year ago

Why are you suggesting to use Object[]?

Nikola Despotoski Over a year ago

Avoiding ClassCastException because of the downcast from String to Integer. String can be Object, Object can be Integer, but String cant be Integer (unless parsed or downcasted [if that word suffices])

Steve P. Over a year ago

Fair enough, I figured that it was better to parse or what have you, but I guess it may just be too verbose for no reason...

Nikola Despotoski Over a year ago

That solution is better than mine if the string has extra characters rather then comma and numbers. Then trimming + replacing + parsing one by one is best solution. :)

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