array_search function doesn't check first value

Question

I have an array which gives me correct results when I print it, for example:

[0] => [email protected],
[1] => 0909,
[2] => [email protected],
[3] => 0909

Now, when I want to check if [email protected] is in the array it gives me an error that the value doesnt exist in this array, but when I try for example [email protected] it gives the correct result.

This is a little part of the code: $user is the word I want to search, $arrayname is the array.

if (array_search(strtolower($user),array_map('strtolower',$arrayname))){
//value exist
}
else{
//value does not exist
}

Now [email protected] doesn't exist it says, while [email protected] does exist.

Who has any idea?

The cause is actually in the documentation. "This function may return Boolean FALSE, but may also return a non-Boolean value which evaluates to FALSE. Please read the section on Booleans for more information. Use the === operator for testing the return value of this function." — GolezTrol
– GolezTrol, Commented Aug 1, 2013 at 14:59

DevZer0 · Accepted Answer · 2013-08-01 14:57:15Z

4

array_search returns the index of the value that is found. When you search for the first item it returns 0. which is also means false. change your code so that it reads

if (false !== array_search(strtolower($user),array_map('strtolower',$arrayname))){

an alternative method would be to use in_array

if(in_array(strtolower($user),array_map('strtolower',$arrayname))){

answered Aug 1, 2013 at 14:57

DevZer0

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Comments

Oliver · Accepted Answer · 2017-10-07 16:17:22Z

0

I simply use is_numeric

if (is_numeric(array_search(strtolower($user), $arrayname)) {
    /* do something */
}

answered Oct 7, 2017 at 16:17

Oliver

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