Syntax Error in Python 3.2.1: Unable to write an exception to a ValueError

Question

I'm new at python and recently I've been trying to write a code for a hangman game: a part of the MIT OCW course: Introduction to Computer Science and Programming. My code goes as follows:

def write_words (word, al):
    neww = (list(word))
    newal = (list(al))
    x = 0
    while (x <= (len(newal))):
        z = newal[x]
        y = neww.index(z)
        except ValueError:
            pass
        x = x + 1
        return (z)
        return (y)

when I call the function using write_words ("word", "abcdefghijklmnopqrstuvwxy") I still get the ValueError:'a' is not in list, that is supposed to be corrected with the exception. I 've been trying to figure out the problem, and apparently is a Syntax error. Please, I would be very grateful with any help. My python version is the 3.2.1

You seem to have your return statement inside the while loop with no conditions. That would return from the function in the first loop. Can you please explain what you are trying to do here? — Sukrit Kalra
– Sukrit Kalra, Commented Aug 2, 2013 at 3:55

Sukrit Kalra · Accepted Answer · 2013-08-02 03:57:52Z

4

You don't have a try statement there. The format is try-except. Something like this.

try:
     a = 25 / 0
except ZeroDivisionError:
    print("Not Possible")


# Output: Not Possible

edited Aug 2, 2013 at 3:57

answered Aug 2, 2013 at 3:46

Sukrit Kalra

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