generate md5 of list values in python

Question

i have a list named as abc which have data like this :

{'devicetype': ['nokia'],'userid': ['1234'], 'year': ['2013']}

Now i have to generate the md5 of the values like nokia , '1234' , '2013' for this i had taken these value in variable like this

 devicetype = abc['devicetype']
 userid = abc['userid']
 year = abc['year']

after that i tried to use md5 to generate a hash like this

  authvalue = hashlib.md5()
  authvalue.update(devicetype+userid+year)

it gives me an error "must be string or buffer, not list" i know this will accept just string . but how can i generate the md5 of these list value?

what is auth1 ? You realise that the three variables you have are arrays, too, right? year == ['2013'] — moopet
– moopet, Commented Aug 4, 2013 at 19:11
@moopet : by mistake i put auth1 there . it is authvalue . And yes i know this is a array. how can i generate the hash of it — user21
– user21, Commented Aug 4, 2013 at 19:18

Martijn Pieters · Accepted Answer · 2013-08-04 19:12:14Z

3

You have lists, not strings. Take the first element of each list:

authvalue = hashlib.md5()
auth1.update(devicetype[0] + userid[0] + year[0])

answered Aug 4, 2013 at 19:12

Martijn Pieters

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Comments

Aleksander Bello · Accepted Answer · 2013-08-04 19:24:37Z

1

Martijn Pieters' answer is basically correct, you have lists of a single element. If you have a big dictionary though, manually adding [0] to each entry might be a pain. So instead you can use map() and reduce() to do that for you.

If d is your dictionary with key-value pairs as above, you can do:

values = map(lambda x: x[0], d.values())

d.values() is just a list of the values of your dictionary (in your case, a list of 1-element long lists):

[['1234'], ['nokia'], ['2013']]

By mapping that lambda function to each one of them you get rid of the inner list:

['1234', 'nokia', '2013']

Then you can get the concatenation of all strings by reducing that list:

concat = reduce(lambda x, y: x + y, values, "")

So concat will be:

'1234nokia2013'

which then you can feed to your hashing function.

answered Aug 4, 2013 at 19:24

Aleksander Bello

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2 Comments

stranac Over a year ago

I'd use ''.join(values) instead of that whole reduce(lambda...) mess.

Aleksander Bello Over a year ago

Well, that depends on how much of a functional programmer one is, I guess :)

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