my L1 array contains numbers like 0.029999999999999999 which i want to print off as 0.03
my code works, but gives an error at the end because the last count is out of range. i understand why it breaks, but dont know how to fix it. thanks
count = 1
while L1:
print "%.2f" %L1[count]
count = count + 1
If you want to print all numbers in L1, use:
for x in L1: print '%.2f' % x
If you want to skip the first one, for x in L1[1:]: will work.
Edit: the OP mentions in a comment (!) that their desire is actually to "create a new array" (I imagine they actually mean "a new list", not an array.array, but that wouldn't be very different). There are no "rounded numbers" in the float world -- you can use round(x, 2), but that will still give you a float, so it won't necessarily have "exactly 2 digits". Anyway, for a list of strings:
newlistofstrings = ['%.2f' % x for x in L1]
or for one with decimal numbers (which can have exactly 2 digits, if you want):
import decimal
newlistofnnumbers = [decimal.Decimal('%.2f') % x for x in L1]
Why don't you just loop through the L1 list instead of doing a while loop?
for i in L1:
print "%.2f" % i
Keep it simple :)
L2=["%.2f" %i for i in L1]
2 problems:
Better is, like the others said:
for i in L1:
print "%.2f" % i
and if you also need the index (count):
for (index, item) in enumerate(L1):
print "Element number (0-based) %d is %f" % (index, item)
See also Pythonic expressions for some more nice ways to use python.
