PHP - Creating an array with explode

Question

My php problem is following:

I have this string: $days="Monday* Tuesday* Wednesday*"

I want to create an array like this: $d[1]="Monday"; $d[2]="Tuesday"; $d[3]="Wednesday"

I sense that the solution passes by explode(*, $days) but I couldn't get further

Thank you for your help :)

how about dealing to the source of the $days string to make this easer — user557846
– user557846, Commented Aug 5, 2013 at 22:21

trijin · Accepted Answer · 2013-08-05 22:18:03Z

1

$days="Monday* Tuesday* Wednesday*";
$d=explode('* ', $days);

or

$days="Monday* Tuesday* Wednesday*";
$d=explode(' ', str_replace('*','',$days));

for exclude "*" in end of last word.

answered Aug 5, 2013 at 22:18

trijin

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kwarunek · Accepted Answer · 2013-08-05 22:18:45Z

1

explode('* ', trim($days, '*'));

answered Aug 5, 2013 at 22:18

kwarunek

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Comments

Louis Borsu · Accepted Answer · 2013-08-05 22:19:16Z

1

You should use :

explode("* ", $days)

But IMO, I would use a coma like this :

$days  = "Monday,Tuesday,Wednesday";
$days = explode(",", $days);
echo $days[0]; // => Monday
echo $days[1]; // => Tuesday

answered Aug 5, 2013 at 22:19

Louis Borsu

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anon · Accepted Answer · 2013-08-05 22:18:46Z

0

$days="Monday* Tuesday* Wednesday*";
$exploded = explode('* ',substr($days, 0, -1));
print_r($exploded);

Output:

Array
(
    [0] => Monday
    [1] => Tuesday
    [2] => Wednesday
)

answered Aug 5, 2013 at 22:18

anon

Comments

mpyw · Accepted Answer · 2013-08-05 22:59:49Z

0

<?php
$days = 'Monday* Tuesday* Wednesday*';
$d = array_filter(explode('* ', $days));

answered Aug 5, 2013 at 22:59

mpyw

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