How does C++ 11's array end() find the array end

Question

Given this how does the end() function added in C++ 11 know the end of the array.

user541686 · Accepted Answer · 2013-08-06 06:42:51Z

4

I'm not sure I understand your question... it could be implemented like this maybe?

namespace std
{
    template<class T, size_t N>
    T *end(T (&arr)[N]) { return &arr[N]; }
}

answered Aug 6, 2013 at 6:42

user541686

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13 Comments

Jerry Coffin Over a year ago

@Himanshu: The size of the array is known at compile time. The template basically extracts that information that the compiler already knew.

user541686 Over a year ago

@user2485710: That is correct but how is it relevant to the question?

Xeo Over a year ago

IIRC, in C++ this actually invokes UB due to dereferencing the past-the-end pointer of the array (inside the subscript). The safe way would be &arr[0] + N.

user541686 Over a year ago

@user2485710: In all honestly I'm not understanding what you're trying to say. Maybe Jerry does?

R. Martinho Fernandes Over a year ago

@Mehrdad you're the one that has to provide a reference. The standard prefers to state guarantees, not non-guarantees. Asking someone to provide a standard reference for a non-guarantee is dishonest.

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