How do I create JSON objects programmatically in playframework 2.1 scala

Question

http://www.playframework.com/documentation/2.1.x/ScalaJson

That document says the idiomatic style of json creation is:

import play.api.libs.json.Json
Json.obj( "key" -> "value )

However this fails to compile as String -> String is not String -> Json.JsValueWrapper

It appears that play provides the code needed for implicit conversions in play.api.libs.json.{DefaultReads, DefaultWrites}

How do I get these implicit conversions into scope?

Hugh · Accepted Answer · 2013-08-07 02:20:55Z

1

You've misspelt your import statement; it should be import play.api.libs.json.Json (it's important to remember Scala is case-sensitive). Fixing that, the code works:

scala> :paste
// Entering paste mode (ctrl-D to finish)

import play.api.libs.json.Json
Json.obj("key" -> "value")

// Exiting paste mode, now interpreting.

import play.api.libs.json.Json
res0: play.api.libs.json.JsObject = {"key":"value"}

scala>

answered Aug 7, 2013 at 2:20

Hugh

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2 Comments

The Trav Over a year ago

That was a transcription error, not an error in the code I was running, however after trying again I'm unable to re-create the problem I've had.

The Trav Over a year ago

It is however, a problem I've come across multiple times, so I'd really like to work out what I'm doing wrong

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