str_replace in foreach loop [closed]

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<?php 

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";

$langs = array ('sk', 'en');

foreach ($langs as $lang) {
    $search = '&lang='.$lang;    
    $new = str_replace($search, "", $url);
}

echo $new; // output: http://localhost/news

?>

Q: How to delete all parameters (&lang=en, &lang=sk) from string ?

Thank you in advance

You are looking for parse_url, possibly with http_build_url, or it's PHP-code equivalent. — Wrikken
– Wrikken, Commented Aug 11, 2013 at 18:50
Why don't you have a valid querystring? Do you realize the key collisions? Will your real scenario always require the full destruction of the entire quasi-querystring? I don't see this being a clear, representative, and/or sufficiently challenging. — mickmackusa
– mickmackusa ♦, Commented Aug 14, 2024 at 4:15

putvande · Accepted Answer · 2013-08-11 18:52:43Z

2

What you are doing is creating a new variable $new each time so that won't do anything good with the $url. Try to assign the str_replace back to its original variable like:

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";

$langs = array ('sk', 'en');

foreach ($langs as $lang) {
    $search = '&lang='.$lang;    
    $url = str_replace($search, "", $url);
}

echo $url; // output: http://localhost/news

answered Aug 11, 2013 at 18:52

putvande

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Liam Sorsby · Accepted Answer · 2013-08-11 18:58:41Z

0

You want to use parse_url() http://www.php.net/manual/en/function.parse-url.php and then http_build_query() http://php.net/manual/en/function.http-build-query.php

answered Aug 11, 2013 at 18:58

Liam Sorsby

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1 Comment

mickmackusa Over a year ago

Have you tried to implement this advice with the sample key collisions? Notice there is no leading ? for the querystring.

score 0 · Accepted Answer · 2013-08-11 19:07:37Z

0

An Alternative:

First:

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";
echo preg_replace("#&lang=(en|sk)#", "", $url);

Second:

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";
echo str_replace(array("&lang=en", "&lang=sk"), "", $url);

Update: for long array of $lang:

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";
echo preg_replace("#&lang=(".implode("|", $lang).")#", "", $url);

edited Aug 11, 2013 at 19:07

answered Aug 11, 2013 at 18:55

user1646111

1 Comment

Ing. Michal Hudak Over a year ago

array $langs can contain more values

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