Symfony2 Console Output without OutputInterface

Understanding the matter of ponctual debugging, you can always print debug messages with echo or var_dump

If you plan to use a command without Symfony's application with global debug messages, here's a way to do this.

Symfony offers 3 different OutputInterfaces

• NullOutput - Will result in no output at all and keep the command quiet
• ConsoleOutput - Will result in console messages
• StreamOutput - Will result in printing messages into a given stream

Debugging to a file

Doing such, whenever you call $output->writeln() in your command, it will write a new line in /path/to/debug/file.log

use Symfony\Component\Console\Output\StreamOutput;
use Symfony\Component\Console\Input\ArrayInput;
use Acme\FooBundle\Command\MyCommand;

$params = array();
$input  = new ArrayInput($params);

$file   = '/path/to/debug/file.log';
$handle = fopen($file, 'w+');
$output = new StreamOutput($handle);

$command = new MyCommand;
$command->run($input, $output);

fclose($handle);

Debugging in the console

It is quietly the same process, except that you use ConsoleOutput instead

use Symfony\Component\Console\Output\ConsoleOutput;
use Symfony\Component\Console\Input\ArrayInput;
use Acme\FooBundle\Command\MyCommand;

$params = array();
$input  = new ArrayInput($params);

$output = new ConsoleOutput();

$command = new MyCommand;
$command->run($input, $output);

No debugging

No message will be printed

use Symfony\Component\Console\Output\NullOutput;
use Symfony\Component\Console\Input\ArrayInput;
use Acme\FooBundle\Command\MyCommand;

$params = array();
$input  = new ArrayInput($params);

$output = new NullOutput();

$command = new MyCommand;
$command->run($input, $output);