Scala array iteration unformated output

Question

Here array values are iterate using Iterator and print one by one.

or [My language is not good]

i want to print array values one by one using iteration

package com.aitrich.collection

object IteratorDemo {
def main(args: Array[String]) {

      var myList = Array("a", "number", "of", "words")  

      var l=myList.length

      for( i <- 0 to l){
      var Lst:String=myList.toString()
      val it = Iterator(l.formatted(Lst))
      while (it.hasNext){
         println(it.next())
      }
      }

   }
}

but the output shows

[Ljava.lang.String;@aad33f6
[Ljava.lang.String;@aad33f6
[Ljava.lang.String;@aad33f6
[Ljava.lang.String;@aad33f6
[Ljava.lang.String;@aad33f6

myList foreach println

Prince John Wesley
– Prince John Wesley

2013-08-17 05:23:33 +00:00
Commented Aug 17, 2013 at 5:23 — Prince John Wesley
– Prince John Wesley, Commented Aug 17, 2013 at 5:23

huynhjl · Accepted Answer · 2013-08-17 05:30:31Z

3

In Scala it is more idiomatic to avoid using index to work on collections:

val myList = Array("a", "number", "of", "words") 
myList.foreach(s => println(s))

Note that Iterator(a) creates an iterator with a single element a in it.

If you want to prefix with the index of the element:

myList.zipWithIndex.foreach{ case (s, i) => println(s"$i: $s")}

// 0: a
// 1: number
// 2: of
// 3: words

edited Aug 17, 2013 at 5:30

answered Aug 17, 2013 at 5:24

huynhjl

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2 Comments

Prasanth A R Over a year ago

thnx.. alot.. .

huynhjl Over a year ago

@Mila, By the way I was looking at your other question and you seem to be having difficulties with dealing with arrays. When you see something like this [Ljava.lang.String;@aad33f6, it means you are printing an array, not its element. Arrays are indexed at 0, and to access the first element of array myList you can do myList(0). To access the ith element, myList(i).

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