I want to write a cript for a user to set an installation path. I am using this
read $file_path
cd $file_path
But it does not change to the path saved on that variable. How can i set this exactly because this seems the wrong way?
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2 Answers
read does not use the $ to read the variable. Hence, it should be
read file_path
cd $file_path
5 Comments
HobbitOfShire
same problem even when i change to this
fedorqui
@user2250162 Does the path exist? Try to do
echo $file;path ls $file_path to see if it gets it properly.HobbitOfShire
echo prints the path,but cd does not change directory
fedorqui
Do you use absolute or relative path, @user2250162?
fedorqui
Try
cd "$file_path", that is, inside quotes.Somewhat reading between the lines, I think you are trying to call a script which you expect to change directory of the caller: For example:
myscript:
read file_path
cd "$file_path"
command-line:
./myscript
and you find it hasn't changed the directory. That's because you are running the script in a child process. It changes the current directory of the child, then returns to the parent, which is unaffected.
You need to source the file instead, that is, run the commands in the current process, not a separate one:
. ./myscript
Yes, notice the extra 'dot' . at the start. This is generically known as the source command, and you can use source instead of 'dot' on bash and csh.
