jQuery, how to call a function while passing a variable

Question

I want to use jQuery's .get method to send an ajax call to the server.

I am using this line:

$.get("InfoRetrieve", { },addContent(data));

As you can see I want to call a function call addContent and pass it the data that is retrieved from the server.

The function addContent is below:

function addContent(data){
    $("#0001").append(data);
}

It doesn't seem to work, can you see why.

I am not passing any data at the moment, I have left the {} as I will be soon. — Ankur
– Ankur, Commented Dec 2, 2009 at 7:04

Doug Neiner · Accepted Answer · 2009-12-02 07:04:53Z

6

Just change it to:

$.get("InfoRetrieve", { },addContent);

It will take care of passing data when it calls the function.

answered Dec 2, 2009 at 7:04

Doug Neiner

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1 Comment

Doug Neiner Over a year ago

When you tried to use it like this addContent(data), you were actually triggering the function, not passing a reference to it. By omitting the (data) you passed a reference to your function that $.get could call upon success.

Roy Tang · Accepted Answer · 2009-12-02 07:05:32Z

0

Try wrapping it in a new function object:

$.get("InfoRetrieve", { },function() { addContent(data) });

answered Dec 2, 2009 at 7:05

Roy Tang

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