Use string as object in python

Question

Edited

Alright the whole aim is to find the min latitude in the given objects:

>>>g.nodes
set([v99, v192, v60, v107, v54, v75, v16, v93, v190, v125, v193, v218, v114, v1, v180, v68, v11, v86, v82, v58, v166, v230, v98, v18, v20, v72, v221, v177, v36, v19, v97, v27, v206, v153, v233, v169, v88, v53, v229, v77, v50, v34, v90, v162, v106, v89, v67, v173, v158, v123, v214, v165, v223, v199, v155, v149, v59, v138, v69, v204, v154, v91, v119, v70, v152, v61, v121, v195, v38, v17, v66, v23, v213, v45, v13, v62, v150, v137, v136, v76, v29, v64, v207, v234, v46, v113, v41, v122, v120, v83, v203, v148, v30, v33, v191, v32, v127, v131, v2, v57, None, v81, v157, v104, v226, v139, v79, v200, v100, v186, v170, v175, v109, v172, v132, v9, v160, v96, v10, v198, v52, v87, v14, v163, v51, v144, v228, v21, v215, v201, v212, v187, v135, v209, v232, v164, v126, v161, v22, v115, v6, v133, v85, v171, v12, v183, v182, v31, v42, v111, v55, v80, v35, v211, v143, v24, v95, v56, v112, v178, v231, v4, v194, v92, v124, v117, v151, v219, v146, v94, v168, v101, v220, v39, v8, v105, v44, v40, v216, v7, v208, v197, v145, v202, v185, v205, v116, v48, v222, v217, v188, v134, v47, v5, v73, v227, v108, v156, v28, v224, v210, v176, v3, v37, v74, v167, v181, v15, v159, v118, v63, v25, v102, v110, v196, v43, v174, v103, v225, v142, v179, v128, v84, v129, v147, v78, v184, v141, v140, v189, v71, v65, v130, v49, v26])
>>> v99
v99
>>> v99.latitude
46.933333
>>> type(g.nodes)
<type 'set'>
>>> type(v99)
<type 'org.gephi.scripting.wrappers.GyNode'>
>>> type(v99.latitude)
<type 'float'>

The plugin's documentation: http://wiki.gephi.org/index.php/Scripting_Plugin

Martijn Pieters · Accepted Answer · 2013-08-19 11:07:05Z

2

You can use the locals() function to look up local names:

for i in data:
    print locals()[i]

but you really want to rethink your data structure instead and perhaps use a dictionary to store x and y.

locals() returns the current local namespace as a dictionary. You should treat this dictionary as read-only, especially within functions.

answered Aug 19, 2013 at 11:07

Martijn Pieters

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4 Comments

Diolor Over a year ago

Thanks for your suggestion, however I am working on a ready plug in that has some deficiencies in its API.

Martijn Pieters Over a year ago

@DDL449: External APIs do not set local names.

James Polley Over a year ago

@DDL449 You didn't mention that you were working on "a ready plug in that has some deficiencies in its API.". If you reword your question to tell us more detail about the problem you're trying to solve we might be able to give an answer that better fits your problem.

Martijn Pieters Over a year ago

@DDL449: You may want to update your question with additional information; perhaps we can suggest better solutions for what you are trying to achieve here.

alecxe · Accepted Answer · 2013-08-19 11:07:22Z

2

You can use locals():

In [1]: x = 'hello'

In [2]: y = 'worlds'

In [3]: data = set(['x', 'y'])

In [4]: for i in data:
   ...:     print locals()[i]
   ...:     
worlds
hello

But, you'd better construct a dictionary, smth like:

data = {'x': 'hello', 'y': 'worlds'}

answered Aug 19, 2013 at 11:07

alecxe

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Comments

James Polley · Accepted Answer · 2013-08-19 11:12:16Z

I have a list of objects

A literal list of objects, in the since of the Python data structure called a list, would look like this:

objectlist = ['x', 'y']

What you've described in your code is not a list of objects, it's just several random unassociated objects.

However, it's pretty clear that you aren't after a list of objects. You want to be able to look up "the object I have labelled 'x'" - the right data structure for that is what Python calls a dict - what other languages call a mapping, or an associative array, or a hash table. You can then use the values from data to look up the corresponding values in the dict.

>>> objectdict = {'x': 'hello', 'y': 'world'}
>>> data = set(['x', 'y'])
>>> for i in data:
...     print objectdict[i]
...
world
hello
>>>

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