ruby count based on certain combination

Question

I have data in the following format

"stats": {
    "team": [],
    "outcome": [],
    "rank": []
}

I need to determine if there is a combination of 2 or more results present from the above structure then print something.

So the idea is:

(if stats.team.present? && if stats.outcome.present) || (if stats.outcome.present? && if stats.rank.present) || (if stats.team.present? && if stats.rank.present)

A better way is to create a method to add a counter that its incremented if the team, outcome, rank has a count of greater than 0.

And then check if the counter is greater than 2. Eg:

def my_count
  count = 0

  count += 1 if stats.team.count > 0
  count += 1 if stats.outcome.count > 0
  count += 1 if stats.rank.count > 0

  if count > 1
    return true
  end
end

Are these the only 2 options or is there a cleaner way?

FYI, there is no ++ operator in Ruby.

squiguy
– squiguy

2013-08-20 19:33:02 +00:00
Commented Aug 20, 2013 at 19:33 — squiguy
– squiguy, Commented Aug 20, 2013 at 19:33

user229044 · Accepted Answer · 2013-08-20 20:27:37Z

2

Are these the only 2 options or is there a cleaner way?

A ton of cleaner ways, but the best ones will use many?, part of ActiveSupport.

many? is essentially like any?, but instead of asking if "one or more" meet a condition, it asks if two or more. It's by far the most semantically correct implementation of your question:

stats = { team: [], outcome: [], rank: [] }}

stats.many? { |k,v| v.present? } # false

stats = { team: [1], outcome: [1], rank: [] }}

stats.many? { |k,v| v.present? } # true

You can get slightly more clever with stats.values and Symbol#to_proc to shorten this further, but I don't see the need:

stats.values.many?(&:present?)

edited Aug 20, 2013 at 20:27

answered Aug 20, 2013 at 20:13

user229044♦

241k41 gold badges347 silver badges350 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Zippie · Accepted Answer · 2013-08-20 19:42:17Z

1

No need to transform it into an array:

data = {stats: { team: [], outcome: [], rank: [] }}

if data[:stats].reject{|k,v| v.empty?}.size > 1

edited Aug 20, 2013 at 19:42

answered Aug 20, 2013 at 19:34

Zippie

6,0886 gold badges34 silver badges46 bronze badges

Comments

Arup Rakshit · Accepted Answer · 2013-08-20 19:59:39Z

0

You can do as

data = {"stats" => { "team" => [], "outcome" => [1], "rank" => [] }}
if data["stats"].values.count([]) > 1
    #code
end

edited Aug 20, 2013 at 19:59

answered Aug 20, 2013 at 19:29

Arup Rakshit

119k30 gold badges270 silver badges328 bronze badges

Comments

Alex Teut · Accepted Answer · 2013-08-20 19:35:00Z

-1

First of all, is it hash or object? I will think of hash.

According to your question: some kind of MapReduce may be looking better:

["team", "outcome", "rank"].map{|key| stats[key].present? }.count(true) > 1

answered Aug 20, 2013 at 19:35

Alex Teut

8449 silver badges20 bronze badges

Comments

Luiz E. · Accepted Answer · 2013-08-20 19:42:24Z

-1

You can try map/reduce and can read more here

after map/reduce you can check the output to see if there are any combination

answered Aug 20, 2013 at 19:42

Luiz E.

7,34912 gold badges64 silver badges104 bronze badges

Collectives™ on Stack Overflow

ruby count based on certain combination

5 Answers 5

Comments

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related