How will i invoke the array parameters in java?

Question

public void createDeck() {
    k=0;
    cards=new Card[52];

    for (i=0;i<4;i++) {
        for (j=0;j<13;j++){
            cards[k]=new Card(i,j);
            k++;                
        }
    }
}

public void shuffleDeck(int m){
    Random random = new Random(); 
    Card cardTemp;
    for(i=0;i<m;i++){
        k=random.nextInt(52);
        cardTemp=cards[i%52];
        cards[i%52]=cards[(i+k)%52];
        cards[(i+k)%52]=cardTemp;
    }                   
}

Hello. I want to take i and j which is in

cards[k]=new Card(i,j);

Because i want to show rank an suit by taking this i and j:

    public Card(int suit,int rank){
        this.rank=rank;
        this.suit=suit;
    }

  private final static String[] suits = { "Hearts", "Spades", "Diamonds", "Clubs" };

   private final static String[] ranks  = { "Ace", "2", "3", "4", "5", "6",
       "7", "8", "9", "10", "Jack", "Queen", "King" };

In another class,

deck=new Deck();
deck.createDeck();
deck.shuffleDeck(111);

Should i use another array? I am really confused. I want to give the screen, for example ace hearts after shuffling.

You likely won't need new arrays, but I'm unsure what you're asking. Do you want to find the card which is in k position? — kiheru
– kiheru, Commented Aug 21, 2013 at 8:51
I want to give the screen, for example ace hearts. I know k in cards[k]=new Card(i,j); but i cant take i j here. — CursedChico
– CursedChico, Commented Aug 21, 2013 at 8:53

No Idea For Name · Accepted Answer · 2013-08-21 08:50:46Z

4

it is not clear what are you asking, but i can guess that you want is when you draw a card from the shuffled deck you'll be able to see it's rank and suit. right?

then the answer is to add 2 methods to Card class:

public int getSuit()
{
   return suit;
}

public int getRank()
{
   return rank;
}

and then, when you draw a card:

Card c = cards[k];
int cSuit = c.getSuit();
int cRank = c.getRank();

answered Aug 21, 2013 at 8:50

No Idea For Name

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