I need to insert a string in another string at a specific place. Here's a simple example:
char *a = "Dany S.";
char *b = "My name is *a , I come from ... ";
So, in string b in place of *a I expect to have Dany S.
How to do that ?
2 Answers
The best/easiest way would be to use standard C conventions:
char *a = "Dany S.";
char *b = "My name is %s, I come from...";
char *c = malloc(strlen(a) + strlen(b));
sprintf( c, b, a );
Then c contains your new string. When you're done with c, you will need to free the memory:
free( c );
If you want to use c in an output that terminates the line, then you can declare b as:
char *b = "My name is %s, I come from...\n";
15 Comments
MasterPlanMan
What about the end of line character?
MasterPlanMan
Sizeof of the char* doesn't return the size of the string. Use strlen for that.
Kevin
You still need the
+1 for the null terminator.MasterPlanMan
+1 for ya cause you're a gentlemen.
LorenzoDonati4Ukraine-OnStrike
IMHO it is useful to point out that after that
malloc the OP is in charge to free that memory chunk pointed by c, otherwise he may leak memory (he seems to be a newbie). |
You could use printf i.e.:
#include <stdio.h>
char *a = "Dany S.";
char *b = "My name is %s , I come from ... ";
printf(b, a);
3 Comments
MasterPlanMan
Isn't it sprintf instead?
Steve Barnes
There is the whole family, printf outputs to stdout, fprintf(file, to a file, sprintf to a string then there are the v.. versions without knowing more about what is required ...
MasterPlanMan
The question is not how to print something on screen but to " insert a string in another string".
snprintf.