json_encode url fail

Question

Has anyone way around this bug?

echo json_encode(array('url'=>'/foo/bar'));
{"url":"\/foo\/bar"}

I use Zend_Json and Zend_Json_Expr so I can get even callback functions inside my js object -- but I can't get a url to come out in a usable format!

echo Zend_Json::encode(array(
                         'url'=>new Zend_Json_Expr('/foo/bar'),
                       ), false,
                       array(
                         'enableJsonExprFinder' => true),
                       ));

produces:

{"url":/foo/bar}

which obviously isn't right either..

Is there anyway to get:

{"url":"/foo/bar"}

without having to do anything ridiculous like find a way to regex it out before sending it to stdio?

Jordan Ryan Moore · Accepted Answer · 2009-12-03 20:28:07Z

7

{"url":"\/foo\/bar"} is actually completely valid and correct JSON for "/foo/bar". Try decoding that value using json_decode() or Zend_Json::decode() and it should output your original URL correctly.

answered Dec 3, 2009 at 20:28

Jordan Ryan Moore

6,8872 gold badges28 silver badges27 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Stephen Fuhry Over a year ago

yes, it is correct JSON, and upon further investigation window.location = 'http:\/\/www.google.com\/'; seems to work.. looks like it's as bug in the plugin i'm using :-p

Justin Over a year ago

And, using _Expr essentially just tells the encoder to not put it in quotes or escape the value - much like Zend_Db_Expr.

Collectives™ on Stack Overflow

json_encode url fail

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related