function within function in PHP

Question

Im having trouble getting a function within a function working, do you think what I have below is done rigth? Im not getting the expected results, if you could shed some light on functions within functions i would appriciete it.

thanks

function test1 ()

{

    global x;

    $x=123;

    function test2()
    {
    echo $x;
    }

    test2();

}

What is your expected result? This construct makes hardly sense. What do you need it for? — Pekka
– Pekka, Commented Dec 4, 2009 at 1:38

wallyk · Accepted Answer · 2009-12-04 01:42:35Z

3

It works, but the scope of test2() is limited. For example, this works:

[wally@zf ~]$ cat y.php
<?php
function test1 ()
{
        global $x;
        $x=123;

        function test2()
        {
                global $x;
                echo $x;
        }

        test2();
}

test1();
?>
[wally@zf ~]$ php -f y.php
123[wally@zf ~]$

answered Dec 4, 2009 at 1:42

wallyk

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2 Comments

chicane Over a year ago

wallyk thank you for the insight, this indeed works now. can you explain why you require x to be redeclared once again as a global in the second function?

wallyk Over a year ago

It's so that $x can be seen outside the respective functions. If $x=123 were set outside test1(), there would be no need for test1() to have global $x.

malonso · Accepted Answer · 2009-12-04 01:40:17Z

0

Can't you just include it as another function outside the first function (test1)? I'm having trouble picturing a use-case for this.

answered Dec 4, 2009 at 1:40

malonso

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Comments

Gal · Accepted Answer · 2009-12-04 01:41:30Z

0

You're not calling the function test2 so there's no reason for it to echo $x.

besides, you should construct the function outside, there's no added value in this case.

answered Dec 4, 2009 at 1:41

Gal

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