Managment of JSON objects and JSON arrays

Question

I'm new with JSON and my question might be not very hard, but I can not find the way to deal with my purpose. I'm trying to develop the code so that I can manage some JSON content. In my case the JSON info is:

{"posts":[{"id":1a00b,"name":"Michael Thomson","info":"he is crazy"},
{"id":18,"name":"Jason Williams","info":"he is tall"}]}

Now, I'd like to get the strings from each JSON object (using Java). That's the code I have developed:

HttpResponse response = httpclient.execute(httppost);           
String jsonResult = inputStreamToString(response.getEntity().getContent()).toString();                      
JSONArray jsonArray = jsonResult.getJSONArray("posts");

for (int i = 0; i < jsonArray.length(); i++) 
{
     JSONObject childJSONObject = jsonArray.getJSONObject(i);
     String id = childJSONObject.getString("id");
     String name = childJSONObject.getString("name");
     String info = childJSONObject.getString("info");
}

The error seems to be related with the sentence:

JSONArray jsonArray = jsonResult.getJSONArray("posts");

The method getJSONArray(String) is undefined for the type String

Those are the libraries I'm using to deal with

import org.json.JSONException;
import org.json.JSONObject;
import org.json.JSONArray;

Thank you very much in advance!

It says "The method getJSONArray(String) is undefined for the type String" — SciPhy
– SciPhy, Commented Aug 29, 2013 at 18:21
jsonResult is of type String, but you're treating it like a JSONObject or JSONArray. Wrap the jsonResult in a JSONObject and then get its "posts" property, which will be a JSONArray. — superEb
– superEb, Commented Aug 29, 2013 at 18:25

Jan Dörrenhaus · Accepted Answer · 2013-08-29 18:24:55Z

2

jsonResult is a String. You need to turn it into a JSONObject first.

JSONObject obj = new JSONObject(jsonResult);
JSONArray jsonArray = obj.getJSONArray("posts");

answered Aug 29, 2013 at 18:24

Jan Dörrenhaus

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