I need to use j as a counter and increment it at the same time the i increments. This code just keep on giving me random number for j.
int i, j; // counters
for (i=0, j=1; i<=LENGTH; i++, j++)
{
printf("Player %i "\n", j);
printf("Name:\t");
fgets(name[i], MAXLENGTH, stdin);
...
printf("Player %i "\n", j);
Statement consists of two double quotes.
printf("Player %i \n", j);
or
printf("Player %d \n", j);
try this code:
#define LENGTH 10
#include<stdio.h>
main()
{
int i, j;//counters
for (i=0, j=1; i<=LENGTH; i++, j++)
{
printf("Player j=%i i=%d \n", j,i);
}
}
What about
int i;//counter
for (i=0; i<=LENGTH; i++)
{
printf("Player %i \n", i + 1);
printf("Name:\t");
fgets(name[i], MAXLENGTH, stdin);
...
You don't say what name is, but if it is simply a string, like:
char name[MAXLENGTH];
then fgets will write into the name string starting at the ith element. It is possible you are writing past the end of the name string. If name is defined locally just before your loop, then you could overwriting both i and j with "random" data (i.e. you are performing the namesake of this site).
If this is the case, then you should instead call fgets as follows:
fgets(name, MAXLENGTH, stdin);
i = 0, j = 1is perfectly valid.for (i = 0, j = 1, k = 2; i < 10; i++, j++, k++)does exactly what one might expect.