How to get URL from String on Android

Question

I'd like to extract URL from hi there this is a URL String http://mytest.com.

I tried to use EditText.getURLs but it didn't work for me.

EditText.setText("hi there this is a URL String http://stackoverflow.com");
EditText.getURLs.toString();

How can I get URL from EditText?

Refer the following post to parse the Url from a long string, stackoverflow.com/questions/6384240/… — user2637715
– user2637715, Commented Sep 5, 2013 at 7:45

Andrei · Accepted Answer · 2016-03-10 15:31:56Z

14

Here is the function:

//Pull all links from the body for easy retrieval
private ArrayList pullLinks(String text) {
   ArrayList links = new ArrayList();

   String regex = "\\(?\\b(http://|www[.])[-A-Za-z0-9+&@#/%?=~_()|!:,.;]*[-A-Za-z0-9+&@#/%=~_()|]";
   Pattern p = Pattern.compile(regex);
   Matcher m = p.matcher(text);
   while(m.find()) {
      String urlStr = m.group();
      if (urlStr.startsWith("(") && urlStr.endsWith(")")) {
         urlStr = urlStr.substring(1, urlStr.length() - 1);
      }
      links.add(urlStr);
   }
   return links;
}

edited Mar 10, 2016 at 15:31

answered Sep 5, 2013 at 7:43

Andrei

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Comments

Manoaj J Rathore · Accepted Answer · 2013-09-30 06:55:33Z

1

change input type of your EditText ---- android:inputType="textUri"

and get your url using --- String url=edittext.getText().toString();

answered Sep 30, 2013 at 6:55

Manoaj J Rathore

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Comments

user1884619 · Accepted Answer · 2017-09-11 09:08:15Z

0

Check this library: (https://github.com/robinst/autolink-java)

  compile "org.nibor.autolink:autolink:0.7.0"

Working fine with Android.

Example:

  LinkExtractor linkExtractor = LinkExtractor.builder()
                    .linkTypes(EnumSet.of(LinkType.URL))
                    .build();
            Iterable<LinkSpan> links = linkExtractor.extractLinks(String_with_Link");
            LinkSpan link = links.iterator().next();
            link.getType();        // LinkType.URL
            link.getBeginIndex();  // 17
            link.getEndIndex();    // 32
            final_Url = String_with_Link.substring(link.getBeginIndex(), link.getEndIndex());

answered Sep 11, 2017 at 9:08

user1884619

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