Converting CURL request to HTTP Request Java

Question

I have the following CURL request Can anyone please confirm me what would be the subesquest HTTP Request

      curl -u "Login-dummy:password-dummy" -H "X-Requested-With: Curl" "https://qualysapi.qualys.eu/api/2.0/fo/report/?action=list" -k

Will it be something like ?

    String url = "https://qualysapi.qualys.eu/api/2.0/fo/report/";
    URL obj = new URL(url);
    HttpURLConnection con = (HttpURLConnection) obj.openConnection();

    // optional default is GET
    con.setRequestMethod("GET"); ..... //incomplete

Can anyone be kind enough to help me convert the above curl request completely to httpreq.

Thanks in advance.

Suvi

aliteralmind · Accepted Answer · 2015-07-14 17:03:19Z

18

There are numerous ways to achieve this. Below one is simplest in my opinion, Agree it isn't very flexible but works.

import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URL;
import java.net.URLConnection;

import org.apache.commons.codec.binary.Base64;

public class HttpClient {

    public static void main(String args[]) throws IOException {
        String stringUrl = "https://qualysapi.qualys.eu/api/2.0/fo/report/?action=list";
        URL url = new URL(stringUrl);
        URLConnection uc = url.openConnection();

        uc.setRequestProperty("X-Requested-With", "Curl");

        String userpass = "username" + ":" + "password";
        String basicAuth = "Basic " + new String(new Base64().encode(userpass.getBytes()));
        uc.setRequestProperty("Authorization", basicAuth);

        InputStreamReader inputStreamReader = new InputStreamReader(uc.getInputStream());
        // read this input

    }
}

edited Jul 14, 2015 at 17:03

aliteralmind

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answered Sep 5, 2013 at 13:41

Ashay Thorat

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1 Comment

kishorer747 Over a year ago

You can add maven dependency for org.apache.commons.codec.binary.Base64 from here :  <dependency> <groupId>commons-codec</groupId> <artifactId>commons-codec</artifactId> <version>1.9</version> </dependency>

Community · Accepted Answer · 2017-05-23 10:31:19Z

3

I'm not sure whether HttpURLConnection is your best friend here. I think Apache HttpClient is a better option here.

Just in case you must use HttpURLConnection, you can try this links:

You are setting username/password, a HTTP-Header option and ignore SSL certificate validation.

How to set username/password check this thread: Connecting to remote URL which requires authentication using Java
How to set eader options have a look at this thread: How to modify the header of a HttpUrlConnection
How to ignore SSL certificate validation is described here http://www.obsidianscheduler.com/blog/ignoring-self-signed-certificates-in-java .

HTH

edited May 23, 2017 at 10:31

CommunityBot

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answered Sep 5, 2013 at 13:15

BetaRide

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Comments

ajgeor · Accepted Answer · 2017-10-03 06:37:42Z

-1

Below worked for me:

Authenticator.setDefault(new MyAuthenticator("user@account","password"));

-------
public MyAuthenticator(String user, String passwd){
    username=user;
    password=passwd;
}

answered Oct 3, 2017 at 6:37

ajgeor

1

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