Passing array values to separate method

Question

Read an array of 5 integer values in the main method. Create a separate function that will determine which number is the biggest. Return the biggest value to the main and print it within the main. I started the code but my problem is that I do not know how to pass the values that I read in the main method (the array values) into the function! I started off like this:

import java.util.*;
public class arraybiggest {
    public static int main (String[]args) {
        Scanner in = new Scanner(System.in);
        System.out.println("Enter 5 values: ");
        int [] x = new int[5];
        for (int i=0; i<5; i++) {
            x[i] = in.nextInt();
            return x;
        }
    }
    public static int  passarray(int [ ] value) {

    }
}

Pls help me! Thanks!

Why is your main method returning int? Shouldn't it be void? — Mauren
– Mauren, Commented Sep 5, 2013 at 13:17

Mauren · Accepted Answer · 2013-09-05 13:16:27Z

1

You can just call your function and pass the array to it, like this:

passarray(x);

But first you need to remove the return x; from the loop.

answered Sep 5, 2013 at 13:16

Mauren

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1 Comment

user2750830 Over a year ago

Im still a beginner! So maybe what im doing is wrong. Can you correct the code and post it! Great help... Im trying so much but it is an error!

sr01853 · Accepted Answer · 2013-09-05 13:18:58Z

0

for (int i=0; i<5; i++) {
        x[i] = in.nextInt();
        }
 passarray(x);

answered Sep 5, 2013 at 13:18

sr01853

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Comments

Prabhakaran Ramaswamy · Accepted Answer · 2013-09-05 13:24:41Z

0

import java.util.*;
public class arraybiggest {

   public static int main (String[]args) {
          Scanner in = new Scanner(System.in);
          System.out.println("Enter 5 values: ");
          int [] x = new int[5];
          for (int i=0; i<5; i++) {
             x[i] = in.nextInt();           
         }

         int result = passarray(x);
         System.out.println("the biggest number is:" +result );
   }


  public static int  passarray(int [ ] value) {
        int result=value[0]
        for(int i=1;i<value.length;i++){
            if (value[i] > result) {
                result= value[i];
            }
        }
       return result;
   }
}

edited Sep 5, 2013 at 13:24

answered Sep 5, 2013 at 13:17

Prabhakaran Ramaswamy

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Comments

score 0 · Accepted Answer · 2013-09-10 12:05:56Z

0

    import java.util.*;
    public class arraybiggest {
        public static int main (String[]args) {
            Scanner in = new Scanner(System.in);
            System.out.println("Enter 5 values: ");
            int [] x = new int[5];
            for (int i =0; i<5; i++) {
                x[i] = in.nextInt();
            }
            System.out.println(findMax(x));
        }
        public static int  findMax(int [ ] value) {
            int max = value[0];
            for (int i = 1; i < value.length; i++) {
                if (value[i] > max) {
                    max = value[i];
                }
            }
            return max;
        }

    }

edited Sep 10, 2013 at 12:05

answered Sep 5, 2013 at 13:19

user2742438

2 Comments

user2750830 Over a year ago

i dont understand in: for (int i = 1; i < value.length; i++) statement what value.length is...

user2742438 Over a year ago

It's the size of the integer array 'value'. 'value' is basically integer array x. Look at the line 'System.out.println(findMax(x));' in main - findMax(x) calls findMax with 'x' as value to the parameter called 'value'.

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