create multi array php with two arrays

Question

I have two arrays same like when var_dump:

$arr1 = array (size=2)
    0 => string '10:2' 
    1 => string '10:1'

$arr2 = array (size=2)
    0 => string '[{username:userA,email:[email protected]'
    1 => string 'username:userB,email:[email protected]}]'

Now, i want to result same below:

$result = array (size=2)
    '10:2' => 
         array (size=2)
            'username' => string 'userA' 
            'email' => string '[email protected]' 

    '10:1' => 
         array (size=2)
            'username' => string 'userB' 
            'email' => string '[email protected]'

Thanks for help!

Why are the elements of $arr2 formatted differently? One has [{ at the beginning the other has }] at the end. Why don't those characters appear in $result? — Barmar
– Barmar, Commented Sep 8, 2013 at 2:23
As @Barmar said, it seems like you want to parse the values of $arr2 (usename and password) ! you aren't clear ! — S.Thiongane
– S.Thiongane, Commented Sep 8, 2013 at 2:32

Barmar · Accepted Answer · 2013-09-08 22:17:40Z

1

I think this should do it:

// Turn string "key1:val1,key2,val2,..." into associative array.
function str_to_assoc($str) {
    $str = str_replace(array('[{', '}]'), '', $str); // Remove extranous garbage
    $arr = explode(',', $str);
    $res = array();
    foreach ($arr as $keyvalue) {
        list($key, $value) = explode(':', $keyvalue);
        $res[$key] = $value;
    }
    return $res;

$result = array_combine($arr1, array_map('str_to_assoc', $arr2));

It looks like $arr2 came from improperly parsing JSON by hand (maybe using preg_split()?). If you do:

$arr2 = json_decode($json_string);

then you should be able to get your result with just:

$result = array_combine($arr1, $arr2);

edited Sep 8, 2013 at 22:17

answered Sep 8, 2013 at 2:34

Barmar

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2 Comments

Minh Loc Over a year ago

thanks for help @Barmar. It's JSON. Im using $arr2 = json_decode($json_string); $result = array_combine($arr1, $arr2); This is return same $result

Barmar Over a year ago

Yeah, json_decode() is what I meant -- got a little confused between PHP and Javascript.

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