Handling exception in Javaparser

Question

I am trying to handle the exception produced by Javaparser library due to token error. I used the following code.

String content=getTheSource();
    ByteArrayInputStream bin=new ByteArrayInputStream(content.getBytes());
    try
    {
        CompilationUnit cu=JavaParser.parse(bin);
    } catch (Exception e) {
        // TODO Auto-generated catch block
        //e.printStackTrace();
                    //my handling code here
    }finally{
        bin.close();
    }

However, the exception was never caught and I am getting a different exception generated from somewhere else. I got this exception:

Exception in thread "main" japa.parser.TokenMgrError: Lexical error at line 1, column 16. Encountered: "#" (35), after : "" at japa.parser.ASTParserTokenManager.getNextToken(ASTParserTokenManager.java:2247) at japa.parser.ASTParser.jj_ntk(ASTParser.java:9986) at japa.parser.ASTParser.ClassOrInterfaceBody(ASTParser.java:926) at japa.parser.ASTParser.ClassOrInterfaceDeclaration(ASTParser.java:604) at japa.parser.ASTParser.TypeDeclaration(ASTParser.java:524) at japa.parser.ASTParser.CompilationUnit(ASTParser.java:269) at japa.parser.JavaParser.parse(JavaParser.java:81) at japa.parser.JavaParser.parse(JavaParser.java:94) at misc.CompileTest.main(CompileTest.java:45)

Any idea, how to handle the exception? Thanks in advance

yup, I did. Just I had to catch TokenMgrError, but I was trying to catch an exception, and TokenMgrError is not a subclass of Exception. — Masud Rahman
– Masud Rahman, Commented Oct 20, 2013 at 17:11
Ahh ok, I ended up finding a fork of the project that fixed my errors - github.com/before/javaparser — facetoe
– facetoe, Commented Nov 1, 2013 at 14:32

bresai · Accepted Answer · 2016-12-23 14:00:36Z

1

As the name indicates, TokenMgrError is an error. So you have to catch an Error instead of Exception. If you want to catch both Error and Exception, you can use Throwable instead.

Originally, this error is throwed by JavaCC (TokenMgrError) which is used by Javaparser.

answered Dec 23, 2016 at 14:00

bresai

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Danny · Accepted Answer · 2017-08-10 15:28:55Z

1

From version 3 on, JavaParser will/should not throw this error anymore.

answered Aug 10, 2017 at 15:28

Danny

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