Passing php variable from one file to another?

Question

I have a variable set in my main file (main.php), and need the second file (uploads.php) to reference the variable as it is set in the first file. It is returning undefined right now tho.

The second file is loaded with $.load into the first file: code example below -

Main.php Contents:

<?php $accountName = get_option('account_name'); ?>

<div id="uploads"></div>

<a href="#" onclick="loadUploadsFile()">Load Your Playlist</a>

function loadUploadsFile() {
     jQuery('#uploads').load('uploads.php');
}

Uploads.php file contents

<?php echo $account_name; ?>    <== returns undefined

$url = 'http://www.somewebsite.com/' . $accountName . '/page/'

/* more code below running a query/loop etc. */

As you may be able to tell, I want Uploads.php to reference the variable decleration in Main.php but is is not pulling the value, it is just returning undefined. Uploads.php loads into the uploads div, but without the account name set the content is just blank.

Would I need to pass the variable to Uploads.php through ajax? I've tried session variables but couldn't get that to work. I was trying an ajax request but I am new to it so couldn't get that nailed. Any help would be great.

Praxis Ashelin · Accepted Answer · 2013-09-10 15:57:06Z

2

Session variables should work after all. Make sure you have the following:

In Main.php

session_start();

$_SESSION["account_name"] = "test";

In Uploads.php

echo $_SESSION["account_name"];

answered Sep 10, 2013 at 15:57

Praxis Ashelin

5,2472 gold badges22 silver badges46 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Jeremy Harris · Accepted Answer · 2013-09-10 15:56:27Z

1

You could pass it as a GET parameter in your jQuery call like:

jQuery('#uploads').load('uploads.php?account=<?php echo($accountName);?>');

And then in your uploads.php file get it from the request like:

$accountName = $_GET['account'];

Some other options are storing it in the session, setting a cookie, or using jQuery .post to send it as POST data.

answered Sep 10, 2013 at 15:56

Jeremy Harris

24.7k13 gold badges84 silver badges133 bronze badges

1 Comment

EHerman Over a year ago

Beautiful. Simple and exactly what I was after. I had no idea how to achieve this tho. Thank you so much for the help, you just ended two days of hair pulling! Will mark this as correct when I am allowed to.

J D · Accepted Answer · 2013-09-10 15:58:41Z

1

Since you are doing jQuery, you might want to look at http://api.jquery.com/jQuery.post/.

Your code should be something like (not sure if exactly)

$.post('uploads.php', { account_name: "<?= get_option('account_name') ?>" }, function(data) {
  $('.result').html(data);
});

And then you can use this variable in your uploads.php by referencing $_POST['account_name'].

PS: I assume you are having PHP 5.4x

answered Sep 10, 2013 at 15:58

J D

1,8182 gold badges20 silver badges20 bronze badges

Comments

Ali · Accepted Answer · 2013-09-10 15:57:23Z

0

Save the account name in a session

Main.php

<?php 
session_start();
$accountName = get_option('account_name'); 
$_SESSION['accountName'] = $accountName;
?>

Uploads.php

<?php echo $_SESSION['accountName']; ?>

answered Sep 10, 2013 at 15:57

Ali

3,4364 gold badges19 silver badges31 bronze badges

Collectives™ on Stack Overflow

Passing php variable from one file to another?

4 Answers 4

Comments

1 Comment

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

1 Comment

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related