Python Codeacademy: Making a list with a string

Question

I'm pondering if I could convert this line of code into a list for all these vowels;

if first== 'a' or first =='e' or first == 'i' or first == 'o' or first =='u':"

I'm thinking str[a,e,i,o,u]

pyg = 'ay'
first = original[0]
original = raw_input('Enter a word:')

if len(original) > 0 and original.isalpha():
    print original.lower()
    if first== 'a' or first =='e' or first == 'i' or first == 'o' or first =='u':
        print "vowel"
    else:
        print "consonant"
else:
    print 'empty'


word = original

You should probably move first = original[0] after original = raw_input('Enter a word:') — DaoWen
– DaoWen, Commented Sep 13, 2013 at 2:15

smac89 · Accepted Answer · 2013-09-13 02:16:22Z

1

if first.lower() in ['a','e','i','o','u']:
    print "vowel"
else:
    print "consonant"

I think the word you are looking for (Beuller) is Boolean?

answered Sep 13, 2013 at 2:16

smac89

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Comments

Crowman · Accepted Answer · 2013-09-13 02:13:44Z

0

You can use a string instead of a list:

if first in "aeiou":
   print "vowel"
else:
   print "consonant"

Bear in mind that your current code prints the first letter in lowercase, but doesn't actually change it to lowercase. You could use:

if first.lower() in "aeiou":

answered Sep 13, 2013 at 2:13

Crowman

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1 Comment

Crowman Over a year ago

Because a string is semantically a list of characters, and Python wants to make things easy for you.

Shashank · Accepted Answer · 2013-09-13 02:15:22Z

0

In Python, str types are like list types in many ways. One of those ways is that the simple and succinct in keyword works just fine for testing membership in both.

pyg = 'ay'
first = original[0]
original = raw_input('Enter a word:')

if len(original) > 0 and original.isalpha():
    print original.lower()
    if first in 'aeiou':
        print "vowel"
    else:
        print "consonant"
else:
    print 'empty'


word = original

answered Sep 13, 2013 at 2:15

Shashank

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Comments

scohe001 · Accepted Answer · 2013-09-13 02:32:02Z

You have a few problems here:

first = original[0]
original = raw_input('Enter a word:')

You're trying to access original before it's defined, this is a simple fix, as it says in the comment (+1 DaoWen), just swap those two lines.

However, then you check to make sure something was entered:

if len(original) > 0

But by then, if original doesn't pass that statement, it will have thrown an error with first = original[0], so it may be better to hold off assigning first until you're in the if block:

original = raw_input('Enter a word:')

if len(original) > 0 and original.isalpha():
    print original.lower()
    first = original[0].lower()
    if first in ['a','e','i','o','u']: print "vowel"
    else: print "consonant"
else:
    print 'empty'

word = original

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