The Perl file 1.pl:
#!/usr/local/bin/perl -w
($b) = @ARGV;
$a = 1;
$c = $a + $b;
print "$c\n";
exit;
The python file 1.py
#!/usr/bin/python
# -*- coding: utf-8 -*-
import subprocess
b = 2
res = subprocess.call(["perl", "1.pl", str(b)])
print res
check out put
$python 1.py
output:
3
0
the output should 3,so what's wrong?
0 is the returncode attribute.
$perl so.pl 2
3
$ echo $?
0 #this gets stored in `res`
Just use :
subprocess.call(["perl", "1.pl", str(b)])
If you don't want that 0 in the output.
You can also use subprocess.check_output to store the output of a command in a variable.
>>> res = subprocess.check_output(["perl", "so.pl", '2'])
>>> print res
3
0 from the python. i. e you are storing the result in res variable and 3 is printing from the perl program
In your perl script you use print to print something to screen, and exit to return a value. Calling exit without a number is equivalent to exit 0, which usually stands for success.
In your case your perl will print 3 and return 0.
Later the python ignores the 3 and prints the 0.
If you want to pass a number from your perl to your python either return that number using exit $c in perl or tell python to check the output of of your perl.
