Java: how to output double-type number to integer format if its decimal is 0

Question

I have an array of double-type numbers {1.0, 2.3, 3.45, 7.8, 9.0, 5.0}. When outputting the numbers, I want to have those with decimal of 0 to show up like an integer: for example, 1.0 => 1, 9.0 => 9.

In java, how do you do this easily? thanks

DecimalFormat or if it's console System.printf() like in c — nachokk
– nachokk, Commented Sep 16, 2013 at 18:13
stackoverflow.com/questions/2683324/java-char-array-to-int Try this link to a question asked before — user2570503
– user2570503, Commented Sep 16, 2013 at 18:21
DecimalFormat df = new DecimalFormat("#.##"); df.parse(3.0D); — nachokk
– nachokk, Commented Sep 16, 2013 at 18:22
@nachokk An alternate to System.printf() for non-console stuff is String.format(). — AJMansfield
– AJMansfield, Commented Sep 16, 2013 at 19:04

brickBreaker · Accepted Answer · 2013-09-16 19:02:02Z

7

Not using any libraries I'd suggest:

public static String parse(double num) {
    if((int) num == num) return Integer.toString((int) num); //for you, StackOverflowException
    return String.valueOf(num); //and for you, Christian Kuetbach
}

Casting a double to int will cut off decimal places.

Feel free to convert the number to a string in whatever way you please ;)

edited Sep 16, 2013 at 19:02

answered Sep 16, 2013 at 18:39

brickBreaker

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3 Comments

tilpner Over a year ago

Would you please use Integer.toString? In my opinion it's better style than ""+anything...

Christian Kuetbach Over a year ago

I would use String.valueOf() :)

tilpner Over a year ago

Or that one, but String.valueOf calls Integer.toString internally, so it's one method call less. Not worth worrying about though...

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