'numpy.float64' object is not callable

Question

I get the error as in the title of my post. I have seen this come up in other questions, but I am interested in understanding what this means since the other answers were in a specific context that does not apply to me.

Secondly, I would like to understand how this applies to my code, shown below. Note that this all works OK if Zindx = 0, but not for any other case.

    Zindx = list(E).index(0)
    for m in range(0,N):
            if m != Zindx:
                for n in range(0,N):
                    if n != Zindx:
                        if n != m:
                            x[m,m] = x[m,m] (
                            - (E[n]-E[m] + E[n])*x[m,n]*x[n,Zindx]
                            /x[m,Zindx]/E[m]
                            )

Your problem is where you do x[m, m] = x[m, m] ( ... ). You probably want to stick a *, or some other operator, between x[m, m] and the (: otherwise, Python is interpreting that as calling object x[m, m] with the arguments inside the parentheses. — Jaime
– Jaime, Commented Sep 23, 2013 at 23:54

A.E. Drew · Accepted Answer · 2013-09-23 23:54:17Z

3

This:

x[m,m] (
    - (E[n]-E[m] + E[n])*x[m,n]*x[n,Zindx]
    /x[m,Zindx]/E[m]
    )

Is trying to call x[m,m] as a function with the expression within the parenthesis as an argument. I am guessing x[m,m] returns a float. Do you mean to multiply x[m,m] by the term in the parenthesis? If so, add the *.

answered Sep 23, 2013 at 23:54

A.E. Drew

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1 Comment

Mark Over a year ago

Yeh, that was very stupid of me. I read that parentheses can be used for equations that run on multiple lines, but clearly this can only work if they are used with the same syntax. I was too busy looking at all the other possibilities that I never noticed...

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