Is there a Lua string.find without pattern

Question

I apply a function, but looks so bad.

function find_without_pattern(s1,s2)
    for i =1,#s1-#s2+1 do
        local t = string.sub(s1,i,#s2+i-1)
        if t == s2 then
            return i,i+#s2-1
        end
    end
end

Yu Hao · Accepted Answer · 2013-09-24 07:04:39Z

12

The string.find method provides an optional 4th parameter to enforce a plaintext search by itself.

For example:

string.find("he#.*o", "e#.*o", 1, true)

will give you the correct results.

Quoting the Lua manual pages:

string.find (s, pattern [, init [, plain]])

A value of true as a fourth, optional argument plain turns off the pattern matching facilities, so the function does a plain "find substring" operation, with no characters in pattern being considered magic. Note that if plain is given, then init must be given as well.

edited Sep 24, 2013 at 7:04

Yu Hao

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answered Sep 24, 2013 at 6:44

hjpotter92

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1 Comment

Yu Hao Over a year ago

Nice, turns out I did the unnecessary work. I also edited your answer since I've deleted mine.

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