How do I convert a user-input integer into a char ASCII value in java?

Question

I am trying to make a program where you can enter a credit card number and it will spit out the number back at you with a ASCII letter/symbol on the end using the remainder of the added digits divided by 26. I feel like my code is right although when I run the program, no symbol shows up. I do not get debug errors or anything, but my (char) symbol just doesn't show up. All it shows is the numbers. Can someone help me please?

Here is what I have so far:

import java.util.*;
import java.text.*;
import java.math.*;

public class Program{

public static void main (String []args){

Scanner keyboard = new Scanner(System.in);

int CC, CC2, CC3, CC4;


System.out.println("Enter your credit card number 2 numbers at a time (XX XX XX XX)");
CC=keyboard.nextInt();
CC2=keyboard.nextInt();
CC3=keyboard.nextInt();
CC4=keyboard.nextInt();

 int CC6;

CC6= (CC+CC4+CC2+CC3)%26;

char CC7;

CC7 = (char)CC6;


System.out.println("The correct number and code is:" +CC+CC2+CC3+CC4+CC7);    

}
}

Pro tip: If you're using Eclipse, pressing Ctrl+Shift+F will format your code nicely, and pressing Ctrl+Shift+O will clean up your imports. Consider doing that before posting! — Meesh
– Meesh, Commented Sep 26, 2013 at 3:58

Community · Accepted Answer · 2017-05-23 11:59:52Z

1

I believe you're looking for

Character.toChars(CC6);

Make sure that when you're testing, you're using a value which actually maps to a decent looking value. For example Character.toChars(65) results in 'A'.

For further reference, see: Converting stream of int's to char's in java

edited May 23, 2017 at 11:59

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answered Sep 26, 2013 at 3:53

Meesh

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2 Comments

user2817797 Over a year ago

When I tried that it just gave me the number instead of the character? code CC6= ((CC+CC4+CC2+CC3)%26)+65; Character.toChars(CC6); System.out.println("The correct number and code is:" +CC+CC2+CC3+CC4); System.out.println(+CC6);

Meesh Over a year ago

Character.toChars(int) returns a char[]. You need to either store it somewhere, or use it directly in the println.

Rahul · Accepted Answer · 2013-09-26 03:55:29Z

0

Print them separately and you can see some weird symbol coming in the console.

System.out.println("The correct number and code is:" + CC + CC2 + CC3 + CC4);
System.out.println(CC7);

The thing is, you'll get the CC7 in the range of 0-25 only since you're doing a mod 26 and this range contains ASCII codes of non-character keys.

Actual character(or for that case, special characters) start from ASCII code 33. Have a look at the ASCII table here.

answered Sep 26, 2013 at 3:55

Rahul

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Comments

ug_ · Accepted Answer · 2013-09-26 03:53:19Z

0

There is a character there its just one that isnt display well with the console. Probably being rendered as a blank space. I see you are using the remainder of 26 so im guessing you want it to be a letter (a-z). The ascii characters for letters start at 65 for capitals and 97 for lower case.

Make this change

CC6= (CC+CC4+CC2+CC3)%26+65;

and you will see a letter between A and Z being printed out.

You can view the full ASCII table here http://www.asciitable.com/

answered Sep 26, 2013 at 3:53

ug_

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