Issue passing a array to a variable argument character parameter

Question

I'm creating anonymous array and passing it to a method which is declared to receive a variable argument character...

I'm wondering how the below code will run successfully, I'm passing a array of characters {'A','B','C,'D'} and the method can receive only characters...shouldn't it fail with wrong types passed? ie; character array vs characters?

public class test {


    public static void main(String[] args) {
        callme(new char[]{'A','B','C','D'});
    }

    static void callme(char... c){
        for (char ch:c){
            System.out.println(ch);
        }

        }

}

char... is some sweet sugar.

Sotirios Delimanolis
– Sotirios Delimanolis

2013-09-26 20:36:12 +00:00
Commented Sep 26, 2013 at 20:36 — Sotirios Delimanolis
– Sotirios Delimanolis, Commented Sep 26, 2013 at 20:36

Peter Lawrey · Accepted Answer · 2013-09-26 20:36:41Z

3

They are the same. A char... is a char[]

You can also write

public static void main(String[] args) {
    callme('A','B','C','D');
}

static void callme(char... c){
    for (char ch : c) {
        System.out.println(ch);
    }

answered Sep 26, 2013 at 20:36

Peter Lawrey

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Comments

Louis Wasserman · Accepted Answer · 2013-09-26 20:36:26Z

1

This will work fine. All the varargs syntax with char... actually does is that it is actually implemented as callme(char[] c), and all the callers of that method who just pass in comma-separated chars will be converted to passing in an anonymous array, exactly as you did by hand.

answered Sep 26, 2013 at 20:36

Louis Wasserman

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