I am creating project in arduino. In C. How can I check if return char is existing in my array?
This is how I want it.
char n[20];
char *adminName[] = {"Jane", "Joe", "James"};
I want to return true if (n) is in my list.
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1Here is duplicateDeepak Ingole– Deepak Ingole2013-09-27 08:35:22 +00:00Commented Sep 27, 2013 at 8:35
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@captain Not really a duplicate of that post, since that post requests a blacklist of characters. There are likely a bunch of others that ask for this, though.user4815162342– user48151623422013-09-27 09:04:26 +00:00Commented Sep 27, 2013 at 9:04
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3 Answers
Loop over array indices and use strcmp(n, adminName[i]) == 0 to test whether the string n is part of the array.
Comments
There are many built in functions are there for this. why cant you use those functions rather than checking manually by loops?
2 Comments
user4815162342
There is a built-in function that searches for a string in an array of strings? Which one?
user4815162342
That sounds like Java or C++, there is no such function in C.
you have to use the strcmp() that check the diff between 2 char *
char n[20];
char *adminName[] = {"Jane", "Joe", "James"};
int i;
i = 0;
while (admminName[i])
{
if (strcmp(n, adminName[i]) == 0)
return (true);
i++;
}
return (false);
1 Comment
Ross McNab
The adminName[] array does not have a NULL entry - your while loop will go past the end of the array.