Fatal error: cannot use stdClass as array

Question

I've inherited some code from an ex-colleague and as it has recently been put into production it is causing us some issues. I'm not a php developer so apologies if this appears vague but it has fallen to me (don't ask!).

We are calling a function getLoan() to pre-populate an application form from an existing application. This should return an array, but I am receiving the stdClass error.

$result = getLoan(); //this is the line that is erroring
if (isset($result->GetResult->Debtor->Addresses->Address[0])) $current_address = clone     $result->GetResult->Debtor->Addresses->Address[0];
else $current_address = clone $result->GetResult->Debtor->Addresses->Address;

if ($result === false)
{
  echo("No LID given");
  die;
}
$attr = 'selected';

and the function:

function getLoan() {
//globals
/*
global $client;
global $test;
global $result;
*/
global $thisurl;

if (isset($_GET['LID'])) 
         $pLoanID = $_GET['LID'];
else 
         return false;
$test = array(
        "pLoanID" => $pLoanID,
);

//print_r($Address); //print address object as a test
//send to gateway starts**********
$url = "https://www.blahblah.asmx?WSDL";
$client = new SoapClient($url, array("trace" => 1, "exception" => 0));

try {
    $result = $client->Get($test);
}
catch(Exception $e) {
    //header("Location: http://" . $_SERVER['REMOTE_ADDR'] . "/application-form-new");
    print_r($e);
    exit;
}

$thisurl = "continue-app?LID=" . $pLoanID;
if (isset($result)) return $result;
else return false;
}

How can I assign the returned value from the function to $result as an array?

Many thanks

you say getLoan() is supposed to return an array, yet you are using it as an object right under its call $result->GetResult — Patrick Evans
– Patrick Evans, Commented Sep 27, 2013 at 11:26

pinkal vansia · Accepted Answer · 2013-09-27 11:28:26Z

1

array = json_decode(json_encode(object),true);

answered Sep 27, 2013 at 11:28

pinkal vansia

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5 Comments

ajguk Over a year ago

$result = json_decode(json_encode(getLoan(),true)); expects parameter 1 to be string

pinkal vansia Over a year ago

json_decode() returns array if you pass true as a second parameter. Basically you pass json encoded object to json_decode with true as a second parameter and it will return array of that object. that is how i interchange between array and object

pinkal vansia Over a year ago

@ajguk you are doing it wrong please check the format of function calls and open and close braces

ajguk Over a year ago

$result = json_decode(json_decode(getLoan()),true); - same error

ajguk Over a year ago

My apologies. I am now getting "Trying to get property of non-object" - for $result

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