PHP Dynamic Include Help on Index.php?

Question

I need someone to let me know a solution to this issue. I am trying to create an include on my index.php file so when a user clicks a link on my navbar the content on the index.php changes. The code below works great, except when I go to index.php, because it is not part of the array, it calls main.php twice, instead of once. I know this is because of the last portion that says:

    else {
    include('main.php');
    }

However, I need a solution to this because I am not good with php. Here is my full code for the include.

    <?php
    // Place the value from ?page=value in the URL to the variable $page.
    $page = $_GET['id'];
    // Create an array of the only pages allowed.
    $pageArray = array('index','css-pub1','page2','page3','page4','page5','page6');
    // If there is no page set, include the default main page.
    if (!$page) {
    include('main.php');
    }
    // Is $page in the array?
    $inArray = in_array($page, $pageArray);
    // If so, include it, if not, emit error.
    if ($inArray == true) {
    include(''. $page .'.php');
    } 
    else {
    include('main.php');
    }
    ?>

include_once() may be a solution.

Armage
– Armage

2013-09-27 16:27:14 +00:00
Commented Sep 27, 2013 at 16:27 — Armage
– Armage, Commented Sep 27, 2013 at 16:27

Vahid Hallaji · Accepted Answer · 2016-07-14 09:34:38Z

1

Try to use include_once instead of include:

include_once($page . '.php');
//...
include_once('main.php');

edited Jul 14, 2016 at 9:34

answered Sep 27, 2013 at 16:27

Vahid Hallaji

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Comments

Leetbulb · Accepted Answer · 2013-09-27 16:31:25Z

1

Just remove

if (!$page) {
    include('main.php');
}

and let the else handle main.php

answered Sep 27, 2013 at 16:31

Leetbulb

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Comments

Jason · Accepted Answer · 2013-09-27 16:27:19Z

0

It's because you're trying to grab the wrong $_GET parameter. Should be:

$page = $_GET['page'];

If your comments are accurate.

answered Sep 27, 2013 at 16:27

Jason

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2 Comments

Alex Mikhaelson Over a year ago

That doesn't change the issue, it only changes the url of the links, so instead of using index.php?id=page1, its now index.php?page=page1.

Jason Over a year ago

That's the point. Those are your $_GET parameters, so if your url currently is "index.php?page=page1" then you need to use $_GET['page'].

bansi · Accepted Answer · 2013-09-27 16:31:26Z

0

I have commented the code on the problems and fixes.

<?php
// initilize $page
$page='';
// Place the value from ?page=value in the URL to the variable $page.
if (isset($_GET['id'])){ // check if the page is set
    $page = $_GET['id'];
}
// Create an array of the only pages allowed.
$pageArray = array('index','css-pub1','page2','page3','page4','page5','page6');

/* This section is not needed
// If there is no page set, include the default main page.
if (!$page) {
include('main.php');
}
*/

// Is $page in the array?
$inArray = in_array($page, $pageArray);
// If so, include it, if not, emit error.
if ($inArray == true) {
include(''. $page .'.php');
} 
else {
// If there is no page set, include the default main page.
// this also does the same thing as the commented if loop above
include('main.php');
}
?>

answered Sep 27, 2013 at 16:31

bansi

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3 Comments

Barmar Over a year ago

I think he wants the main.php stuff even when he includes other pages, he just doesn't want it twice.

bansi Over a year ago

@Barmar not clear from OP's question. From his code comments it looked like he wants either one of the pages only

Barmar Over a year ago

He says it works as desired when he goes to one of the other pages, it's only a problem when he goes to index.php.

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