How do I convert a a string of datetime into datetime format in python so that it can be compared with another date?
string_date = "2013-09-28 20:30:55.78200"
abc = datetime.datetime.now()
if abc > string_date :
print True
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2 Answers
The particular format for strptime:
datetime.datetime.strptime(string_date, "%Y-%m-%d %H:%M:%S.%f")
#>>> datetime.datetime(2013, 9, 28, 20, 30, 55, 782000)
You should use datetime.datetime.strptime:
import datetime
dt = datetime.datetime.strptime(string_date, fmt)
fmt will need to be the appropriate format for your string. You'll find the reference on how to build your format here.
5 Comments
Praful Bagai
You mean to say
dt = datetime.datetime.strptime(string_date, "YYYY-MM-DD %H:%M%:%S") ?
Thomas Orozco
@user1162512 That format will not be correct, check my updated answer.
Praful Bagai
not working with
dt = datetime.datetime.strptime(string_date, "YYYY-MM-DD %H:%M%:%S") . Says format is not valid
Ben
It's not valid @user1162512, as you were told. For a start your string has fractional seconds, which you haven't accounted for in your format. If you read the documentation it'll help.
Praful Bagai
Thanks. It worked with the answer provided by @Veedrac