javascript replace \ character

Question

i've a pure javascript var containing the following value:

    var a = "\\{0\\}";

now what i need to do is replace the two \ before the first and latter bracket.

I've tried different solution, but no one seems to work

   var b = a.replace(pattern,'')

I can't find a good pattern. I don't know what to do or how to write a good pattern or a regexpr.

Anyone know the solutions? Thank to all

P.S. I need the solution in pure javascript.

duplicate of stackoverflow.com/questions/6640382/…

davidkonrad
– davidkonrad

2013-09-30 14:34:37 +00:00
Commented Sep 30, 2013 at 14:34 — davidkonrad
– davidkonrad, Commented Sep 30, 2013 at 14:34

Tyler · Accepted Answer · 2013-09-30 15:33:03Z

2

var a = "\\{0\\}";
var pattern = /\\/g;
var b = a.replace(pattern,'');

Your problem is that you're dealing with escape characters, so you needed to use a regex.

edit: working example

http://jsfiddle.net/tylerpachal/HgBnw/

edited Sep 30, 2013 at 15:33

answered Sep 30, 2013 at 14:32

Tyler

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2 Comments

user2548436 Over a year ago

Thank you TylerAndFriend, but i've already tried your suggest and it doens't work. I've found the solution, i don't know why but the pattern need \ 3 times var a = "\\{0\\}"; var b = a.replace(/\\\/g, ''); console.log(b) will print {0}

ajp15243 Over a year ago

@user2548436 The above answer, with a pattern of /\\/g, worked for me. In Chrome console, the statement "\\{0\\}".replace(/\\/g, '') yields "{0}". Using a pattern of /\\\/g gives a SyntaxError.

Nitin · Accepted Answer · 2013-09-30 14:35:06Z

1

Try this

var a = "\\{0\\}";
var b = a.replace('\\','').replace('\\','');
alert(b);

answered Sep 30, 2013 at 14:35

Nitin

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