How to include a php include statment in a php variable?

Question

I have a variable including html structure like following:

$txt = '<table>
           <tr>
               <td>
              </td>
           </tr>
       </table>';

I want to write the following statement inside the variable :

include_once('./folder/file.php');

I try to write it like the following but it failed:

$txt = '<table>
               <tr>
                   <td>';
                   include_once('./folder/file.php');
                  $txt.='</td>
               </tr>
           </table>';

And I try it like that and also not work:

$txt = '<table>
                   <tr>
                       <td>
                       {include_once('./folder/file.php');}
                     </td>
                   </tr>
               </table>';

How can I do that? I am sorry not very expert with mixing php and html so a small help will be appreciated ??

include_once is probably not correct in this case since you're doing templating. Use the non-once variant include. — Halcyon
– Halcyon, Commented Oct 1, 2013 at 12:18

Daniel W. · Accepted Answer · 2013-10-01 12:21:25Z

7

Use Output Buffer functions:

ob_start();
include('./folder/file.php');
$include = ob_get_clean();

$txt = '<table>
           <tr>
               <td>' . $include . '</td>
           </tr>
       </table>';

See http://php.net/ob

The output buffer gathers everything you'd send to the browser until you empty, delete or end it.

http://www.php.net/manual/en/function.ob-get-clean.php

edited Oct 1, 2013 at 12:21

answered Oct 1, 2013 at 12:14

Daniel W.

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1 Comment

Daniel W. Over a year ago

can you provide a link or something, you might be using it wrong or mix table html elements wrong

AaronHatton · Accepted Answer · 2013-10-01 12:20:11Z

0

You have to do it as follows i believe it is call concatenating:

$table_content = include_once('./folder/file.php');
$txt = '<table>
               <tr>
                   <td>
                         ' . $table_content . '
                   </td>
               </tr>
         </table>';

or...

$txt = '<table>
               <tr>
                   <td>
                         ' . include_once('./folder/file.php') . '
                   </td>
               </tr>
         </table>';

To put it simply when I ever need to echo some text out followed by a variable the way I do it is to do as follows:

$color = brown
$state = lazy

echo "The quick" . $color . "fox jumped over the" . $state . "dog";

This would give the results of:

The quick brown fox jumped over the lazy dog

For more information see: Concatenate Strings

edited Oct 1, 2013 at 12:20

answered Oct 1, 2013 at 12:14

AaronHatton

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3 Comments

Ben Over a year ago

include returns false or 1, not the content of the file

Ben Over a year ago

no, my bad, you can actually return something from include.. interesting (php.net/manual/en/function.include.php)

Daniel W. Over a year ago

This won't work anyways. If you have a file test.php include into the variable $table_content and you have an echo "blargh"; in there, it will be printed to the browser, outside of the variable

bensiu · Accepted Answer · 2013-10-01 12:56:44Z

0

Try this

$txt = '<table>
           <tr>
               <td>';
$txt.=include_once('./folder/file.php');
$txt.='</td>
           </tr>
       </table>';
print_r($txt);

edited Oct 1, 2013 at 12:56

bensiu

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answered Oct 1, 2013 at 12:35

Pragati

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