PHP $_POST not working with jquery

Question

i am using this jquery code:

<script type="text/javascript">
$(document).ready(function () {
    $("#message").hide();
    $("#please_wait_box").hide();
    $("#editcustomer").submit(function (e) {
        $("#message").hide();
        $("#please_wait_box").show();
        e.preventDefault();
        dataString = $("#editcustomer").serialize();
        $.ajax({
            type: "POST",
            url: "editcustomer_go.php",
            cache: false,
            data: dataString,
            success: function (res) {
                $("#please_wait_box").hide();
                $("#message").html(res);
                $('#message').fadeIn('slow');
                if (res.indexOf("success") != -1) {
                    window.location.href = res.substr(8);
                }
            }
        });
    });
});
</script>

to submit forms without changing the page.

then the editcustomer_go.php echoed results display in:

<div id="message" class="messagebox"></div>
<div id="please_wait_box" class="messagebox">Please Wait...</div>

i am using tinymce for text editors - its working okay but when the data is posted in the PHP, its not seeing the changed data in the tinymce text editor - it has to be plain text.

how can i get round this?

Can you explain its not seeing the changed data in the tinymce text editor - it has to be plain text.? — Reinstate Monica Cellio
– Reinstate Monica Cellio, Commented Oct 2, 2013 at 14:39
For smaller things like mail you use $_POST. If it's getting heavier it's better to use $_DHL. — djot
– djot, Commented Oct 2, 2013 at 14:40
The question title confuses me. How does $_POST fail to work? — Álvaro González
– Álvaro González, Commented Oct 2, 2013 at 14:41
if i echo $_POST["site info_notes"]; which is the textarea name it displays the old data, not the new data i entered into the textarea — user2710234
– user2710234, Commented Oct 2, 2013 at 15:00

Clart Tent · Accepted Answer · 2013-10-02 14:43:05Z

1

To grab the data from TinyMCE you need to use their getContent() function.

So in your case it'd be

// Grab a reference to the editor
var ed = tinyMCE.get('tinymceeditorname');
// Get it's content
var editordata= ed.getContent();

... and then just pass editordata along with the rest of the form as the AJAX call data.

answered Oct 2, 2013 at 14:43

Clart Tent

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1 Comment

Clart Tent Over a year ago

You'd add those two lines inside your $("#editcustomer").submit() function. You'd then need to pass editordata to the AJAX call along with the other data you serialized from your form.

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