0

I have:

data = [[u'text'],[u'element'],[u'text00']]
pattern = text
pattern2 = EL
pattern3 = 00

Using regex I want to search and return:

text, text00 # for pattern
element      # for pattern2
text00       # for pattern3
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6
  • What are you expecting? Commented Oct 3, 2013 at 3:25
  • To find the pattern. If user enters "red" and the list is ["red", "lightred", "orange red", "blue"] then it should return true. Commented Oct 3, 2013 at 3:37
  • That's what if pattern in data: already returns Commented Oct 3, 2013 at 3:38
  • @Haidro I think OP wants "red", "lightred", "orange red" to be returned for red. Commented Oct 3, 2013 at 3:39
  • @SantoshKumar hm, thought so. Just odd how the example structure already has red in it Commented Oct 3, 2013 at 3:40

2 Answers 2

Reset to default
2 
import re
data = [[u'text'], [u'element'], [u'text00']]
patterns = [u'text', u'EL', u'00']
results = []
for pattern in patterns:
    results.append([x[0] for x in data if re.search(pattern, x[0], flags=re.I)])
print  results

or, more concisely:

import re
data = [[u'text'], [u'element'], [u'text00']]
patterns = [u'text', u'EL', u'00']
results = [[x[0] for x in data if re.search(pattern, x[0], flags=re.I)] for pattern in patterns]
print  results
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1 Comment

Yes, that did it, tks!
2

I think what you're looking for is any():

>>> L = ["red", "lightred", "orange red", "blue"]
>>> keyword = 'red'
>>> import re
>>> any(re.search(keyword, i) is not None for i in L)
True
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2 Comments

OK, this is useful butI get: TypeError: expected string or buffer. Please note that L will be a list like this: [[[u'red']], [u'blue'], [[u'lightred']]] and keyword is user input
@rebHelium That's a very odd list. Using the code here, flatten the list, then use my code

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