This code working fine
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet("http://localhost:8090/Servlet/ServletFirst?to=1234&from=567&text=testtest");
If i use space between parameter value. It throws exception
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet("http://localhost:8090/Servlet/ServletFirst?to=1234&from=567&textParam=test test");
space between test test throws error. How to resolve?
You must URL encode the parameter in your URL; use %20 instead of the space.
HttpGet request = new HttpGet("http://localhost:8090/Servlet/ServletFirst?to=1234&from=567&textParam=test%20test");
Java has a class to do do URL encoding for you, URLEncoder:
String param = "test test";
String enc = URLEncoder.encode(param, "UTF-8");
String url = "http://...&textParam=" + enc;
Just use a %20 to represent a space.
This is all part of the URL encoding: http://www.w3schools.com/tags/ref_urlencode.asp
So you would want:
HttpGet request = new HttpGet("http://localhost:8090/Servlet/ServletFirst?to=1234&from=567&text=test%20test");
Use
URLEncoder.encode("test test","UTF-8")
So change your code to
HttpGet request = new HttpGet("http://localhost:8090/Servlet/ServletFirst?to=1234&from=567&textParam="+URLEncoder.encode("test test","UTF-8"));
Note Don't Encode Whole url
URLEncoder.encode("http://...test"); // its Wrong because it will also encode the // in http://
Use %20 to indicate space in the URL, as space is not an allowed character. See the Wikipedia entry for character data in a URL.
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet(
"http://localhost:8090/Servlet/ServletFirst?to=1234&from=567&textParam=test%20test");
%20............? I think there's an URL encoder laying around somewhere...